Simply remove the parentheses and solve. This leaves 10x+1, or Answer 2.
STEP ONE. Cross-multiply (18a=6a2).
STEP TWO. Reverse (6a2=18a).
STEP THREE. Divide by 6 (a2=3a).
STEP FOUR. Take the square root of a (3√a). Answer 4.
40,000*5 weeks of the year=200,000
Pick a number and start high since there is a lot of ground to make up to get to 44,000.
46,000*11 remaining weeks of the year=506,000
Add 506000+200000=706000.
Divide this by 16. 44,125 is the answer, and since that's the closest you'll get to the target, Answer 1 is the correct choice.
Simply plug in your options, and you'll see that 3 is the only answer (Answer 3).
x/4=x-30
CROSS-MULTIPLY. x=4(x-30)
MULTIPLY. x=4x-120
ADD -4x -3x=-120
DIVIDE -3 x=40
Answer 2.
If each pencil case can carry ten pencils (the minimal number of pencils that can be stored in each case), the total number of pencils required is ten plus five, which equals fifty pencils.
Also, if all of the pencil cases have 14 pencils (the maximum number of pencils that each case can carry), the total number of pencils that can be stored is 14 + 5 = 70 pencils.
As a result, the percentage must be between 50 and 70. Only (C), 65 pencils, matches this criteria out of all the available answers.
First, figure out how fast the bird is moving:
$\frac{72 \text{ miles}}{6 \text{ hours}} = 12 \text{ miles per hour}$
In 5 hours, the following distance will be covered:
$12 \text{ mph} * 5 \text{ h} = 60 \text{ miles}$
Utilize the given data to make a framework of equations in two factors and after that unravel with the strategy of combination. Translating the problem statement into algebra:
$x + y = 13$
$x − y = 7$
Include the 2 equations together:
$x + x = 13 + 7;$
Now solve for $x$:
$2x = 20; \, x = 10$
The value of $y$ can then be found by stopping $x$ back into either of the two original conditions:
$10 + y = 13; \, y = 3$
Once the variable values are found, their product can be computed:
$x * y = 10 * 3 = 30$
Set up equivalent proportions:
$\dfrac{x \text{ have mutation}}{163{,}000{,}000 \text{ males}}$ $= \dfrac{4 \text{ have mutation}}{25{,}000 \text{ males}}$
Cross multiply to solve for $x$:
$(25{,}000)(x)$ $= (4)(163{,}000{,}000)$
$x = \frac{(4)(163{,}000{,}000)}{25{,}000}$
$x = 26{,}080 \approx 26{,}000$
