It is apparent from the graph that it is not linear hence the answer cannot be (A) If an attempt is made to solve (B) it will be found there is no real solution. One of the solutions to (D) is 8, which gives a negative value. (C) is the only possible solution.
One third of 84 is 84 × 1/3 = 84÷3 = 28. 28 people 25 years old or younger applied for the job. Two seventh of 84 is 84 × 2/7= 2×84÷7 = 24. 24 people who were at least 50 years old applied for the job. 84 - 28 - 24 = 32. 32 people applied for the job who were between 25 and 50.
h =15 + 3.2t gives the height of a shrub in inches after t weeks. When planting occurs the height is 15 + 3.2× 0 = 15 inches After one week the height is 15 + 3.2× 1 = 18.2 inches The rate at which the height increases is 18.2 - 15 = 3.2 inches
The point on the graph corresponding to t = 1 is (1,8). The point on the graph corresponding to t = 2 is (2,5). The slope of the straight line joining them is (5 - 8)÷(2 - 1) = -3. The equation is T = -3t + c As (2,5) lies the line we can substitute for t and T. 5 = -3×2 + c c = 11 Equation is T = -3t + 11 which is the same as (a)
h =15 + 3.2t gives the height of a shrub in inches after t weeks. When the height is 31 inches 31 = 15 + 3.2t 3.2t = 16 t = 16÷3.2 t = 5 The height is 31 inches after 5 weeks
It can be confirmed by division that (a), (b) and (c) are factors of 450, while 100 is not. The multiples of 25 are 25, 50, 75,.... 75 is both a factor of 450 and multiple of 25
If r = 1 then the surface area of the smaller sphere is 12.56...... If the radius is doubled the surface area is 50.26...... The factor is 50.26... ÷ 12.56.... = 4. The surface area is enlarged by a factor of 4.
Initial means at the beginning. At the beginning t is 0. h =15 + 3.2t gives the height of a shrub in inches after t weeks. When planting occurs the height is 15 + 3.2× 0 = 15 inches
It is clear from the diagram that the T -axis is the mirror line or axis of symmetry of this diagram. The equation of the T- axis is t = 0. The equation of the axis of symmetry of this graph is t = 0
(√3 + √2)2 = (√3 + √2)( √3 + √2) (√3 + √2)( (√3 + √2) = √3×√3 + √3×√2 + √2×√3 + √3×√3 √3×√3 + √3×√2 + √2×√3 + √3×√3 = 3 + √6 + √6 + 2 3 + √6 + √6 + 2 = 5 + 2√6
