The average age of the class is 24 years and there are 24 students.
This means that the total age of all the students combined is 24 * 24 = 576 years.
When the teacher's age is included, the average increases by 1.
This means that the total age of all the students and the teacher combined is 24 * 25 = 620 years.
Therefore, the teacher's age is 600 - 576 = 49 years.
Assume the son is x years old at this point. Based on the available data, the father was three times the son's age ten years ago. Thus, the father was 3x years old ten years ago.
Let's now think about the future. In ten years, the father will be twice as old as his son. Thus, the father will be 2x years old in the future.
We can solve the following equation using this information: 3x + 10 = 2x + 20. After resolving this equation, we get x = 10.
Therefore, the present age of the son is 10 years. And the present age of the father is 3x + 10 = 3(10) + 10 = 40 years.
Their current age ratio is 40:10, which can be simplified to 4:1.
The 5 children who were born 3 years apart add up to 50 years.
We can divide the total age by the number of children, which is 5, to determine the age of the youngest child.
The product of 50 and 5 is 10. Consequently, the youngest child is 10 years old.
Since Meena and Meera have ages that are 4:3, if we assume that they are 4x and 3x, respectively, then the total of their ages is 4x + 3x = 7x.
Since we know that their combined ages equal 28, 7x = 28.
When we solve for x, we get x = 4.
As a result, Meena is 16 years old (4x = 4 * 4) and Meera is 12 years old (3x = 3 * 4).
Meena will be 16 + 8 = 24 years old after 8 years, and Meera will be 12 + 8 = 20 years old.
After eight years, their age ratio is 24:20, which can be simplified to 6:5.
