Explanation:
If a $20,000 car will only be worth $755 at the very least, that means the car will lose $19,245 in value over the course of 15 years ($20,000 – $755 = $19,245).
Every year, $1,283 is lost ($19245 x 15).
As a result, the formula is 1,283T + 20,000.
Explanation:
First, subtract 4 from both sides to isolate the variable, Then, divide both sides by 16 to solve for x:
16x + 4 - 4 = 100 - 4
16x = 96
16x/16 = 96/16
x = 6
Explanation:
Tinalco Year 1: Alcom plc's Year 2
900,000: 450,000
900,000 / 450,000 = 2 = 1:0.5
Explanation:
Step 1 - Calculate the value of standard cogs sold:
Number of standard cogs = total - substandard: 10,000 - 3,000 = 7,000 Standard cogs
Each cog worth $1.99, so total = 7,000 x $1.99 = $13,930
Step 2 - Calculate the value of substandard cogs sold
Number of substandard cogs = 3,000
Value of each = 20% of standard value: 0.2 x $1.99 = $0.398 = $0.40 to nearest cent
Total: $0.4 x 3,000 = $1,200
Step 3 - Total
13,930 + 1,200 = $15,130
Explanation:
March total = 7,000 cogs
March substandard = 1,000 cogs
7,000 - 1,000 = 6,000 cogs
April total = 8,000 cogs
April Substandard = 3,000 cogs
8,000 - 3,000 = 5000 cogs
6,000 + 5,000 = 11,000
Explanation:
March substandard = 1,000
May substandard = 3,000
Total = 4,000
Total March = 7,000
Total May = 10,000
Overall Total = 17,000
4,000 / 17, 000 × 100 = 23.5%
Explanation:
April cog production = 8,000
Feb cog production = 4,000
8,000-4,000 / 4,000 ×100 = 100%
