Since,
2C = A + B ----(i)
C plus D equals 2A--(ii)
A + B + C + D = 2C + 2A => B + D = A + C is what we obtain by adding (i) and (ii).
?= (3 + 4 - 2 - 1) + (1/6 + 1/2 - 2/3 - 11/12)
= 4 * [(2+6-8-11)/12]
= 4 - 11/12 = 31/12.
After swapping out 4 and 8 and + and - in (b), we obtain the following equation:
12 - 4 + 8 = 0
or 12-12.12 = 0
or 0 = 0, which is true.
Employing Accurate Symbols, We've Got: Equation given is 30 / 2 + 3 x 6 - 5 = 15 + 18 - 5 = 28.
It is evident that 5 - 0 + 3 X 5 = 20
Let a, b, c, d, and e represent the runs that P, Q, R, S, and T scored.
Using the provided data,
a + b + c + d + e = 36 x 5 = 180
b + c = 107
Let a = x
e = x-8
d = x-3
now 3x - 11 + 107 = 180
3x = 84
x = 28
e's score = 28-8 = 20
After swapping +, x, and 4 and 5 in (c), we obtain the following equation: It is correct that 4 + 5 x 20 equals 104 or 104 = 104.
Given the given data, we can express:
20 - 8 ÷ 4 × 2 = 20 - 8 - 2 × 2 = 20 - 4 = 24.
Upon swapping - and /, we obtain the following equation:
5 plus 3 x 8 / 12 - 4 = 3
or 5 + 3 x (2/3) - 4 = 3.
or 3 = 3, which is true.
In this case, 12 x 2.5 = 30
Likewise, 14 x 2.5 = 35
With the trial-and-error approach,
The solutions for u = 1 and v = 3/2 satisfy both equations.
