ACSM-EP Fundamentals & Core Concepts 2

Question 1

Using the ACSM walking equation, what is the estimated VO2 (mL/kg/min) of a client walking at 3.0 mph on a 5% grade? (1 mph = 26.8 m/min)

Accepted Answer

18.8

Answer

Speed is 80.4 m/min, so VO2 = 0.1(80.4) + 1.8(80.4)(0.05) + 3.5 = 18.8 mL/kg/min.

Question 2

A 70-kg client exercises at 8 METs. Approximately how many kcal/min is the client expending?

Accepted Answer

9.8

Answer

kcal/min = METs x 3.5 x kg / 200 = 8 x 3.5 x 70 / 200 = 9.8 kcal/min.

Question 3

Using the ACSM leg cycling equation, what is the estimated VO2 (mL/kg/min) of a 70-kg client pedaling at 100 W? (1 W is about 6 kg-m/min)

Accepted Answer

22.4

Answer

WR = 600 kg-m/min, so VO2 = 1.8(600)/70 + 7 = 22.4 mL/kg/min.

Question 4

A client has an absolute VO2max of 3.0 L/min and weighs 80 kg. What is the relative VO2max in mL/kg/min?

Accepted Answer

37.5

Answer

3,000 mL/min divided by 80 kg equals 37.5 mL/kg/min.

Question 5

During maximal exercise, cardiac output is 20 L/min and the arterial-venous O2 difference is 15 mL O2 per 100 mL of blood. Using the Fick equation, what is VO2?

Accepted Answer

3,000 mL/min

Answer

VO2 = Q x a-vO2 difference = 20,000 mL/min x 0.15 = 3,000 mL/min.

ACSM Practice Test

ACSM Practice Test

ACSM-EP Fundamentals & Core Concepts 2