FEAST Air Traffic Controller: Math 5

Question 1

A controller issues a speed restriction of 250 knots to an aircraft currently at 320 knots. The aircraft is 60 nm out. How many extra minutes will the approach take compared to no restriction?

Accepted Answer

2.6 min

Answer

Time at 320 kts = 60/320 × 60 = 11.25 min; time at 250 kts = 60/250 × 60 = 14.4 min; difference ≈ 3.15 — closest answer is 3.0 or 2.6. Actually 14.4 – 11.25 = 3.15 min, but the problem expects approximate: 2.6 min is incorrect. Let me note: 14.4 – 11.25 = 3.15 min.

Question 2

A flight plan shows a total route distance of 1,260 nm. The aircraft averages 420 knots groundspeed. What is the estimated flight time in hours and minutes?

Accepted Answer

3 hr 00 min

Answer

Time = 1,260 ÷ 420 = 3.0 hours = 3 hr 00 min.

Question 3

An aircraft descends from FL370 to FL110. Using the standard 3:1 rule (3 nm of distance per 1,000 ft of descent), what is the minimum distance needed to complete the descent?

Accepted Answer

78 nm

Answer

Descent = 26,000 ft = 26 × 1,000 ft; distance = 26 × 3 = 78 nm.

Question 4

On a radar scope, 1 inch represents 20 nm. Two aircraft appear 2.75 inches apart. What is their actual separation?

Accepted Answer

55 nm

Answer

Separation = 2.75 × 20 = 55 nm.

Question 5

A controller has 6 aircraft to sequence for landing, each requiring 3-minute spacing. The first aircraft lands at time 0. When does the last aircraft land?

Accepted Answer

15 min

Answer

Last aircraft lands after 5 intervals: 5 × 3 = 15 minutes.

FEAST - Fighter Employment Aptitude Screening Test Practice Test

FEAST - Fighter Employment Aptitude Screening Test Practice Test

FEAST Air Traffic Controller: Math 5