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Renewable Energy Flashcards

7 cards from real Agricultural/Bioengineering practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 Renewable Energy flashcards as text
  1. Which anaerobic digestion product can be used directly as a vehicle fuel after upgrading to remove CO2?

    Answer: Biogas (biomethane)

    Biogas upgraded to remove CO2 and H2S becomes biomethane, which meets natural gas vehicle fuel standards.

  2. In a wind energy system for an agricultural operation, what is the purpose of a charge controller?

    Answer: Prevents battery overcharging by regulating current flow

    A charge controller regulates the voltage and current from the wind turbine to prevent battery damage from overcharging.

  3. A farm uses a micro-hydropower turbine. If flow rate doubles but head remains constant, how does power output change?

    Answer: Power doubles

    Hydropower is P = ρgQH, so doubling flow rate Q directly doubles power when head H is constant.

  4. Which feedstock produces the highest methane yield per unit of volatile solids in anaerobic digestion?

    Answer: Fats and oils

    Fats and oils yield approximately 1,000 L CH4/kg VS, the highest among common organic substrates.

  5. What does the term 'net metering' allow agricultural solar installations to do?

    Answer: Sell excess electricity back to the grid and receive credit on utility bills

    Net metering allows farms to export surplus solar generation to the grid and offset future electricity costs.

  6. In bioengineering, which enzyme complex is responsible for breaking down cellulose into fermentable sugars?

    Answer: Cellulase

    Cellulase is the enzyme complex (including endoglucanase, exoglucanase, and β-glucosidase) that hydrolyzes cellulose into glucose.

  7. A solar thermal collector on a grain dryer has an efficiency of 60% and receives 800 W/m² insolation. What is the useful heat output per square meter?

    Answer: 480 W/m²

    Useful output = efficiency × insolation = 0.60 × 800 = 480 W/m².