Raven's Progressive Matrices Simultaneous Rule Application Flashcards

In a 3x3 matrix, two rules are applied simultaneously. Rule 1, applied across the rows from left to right, is that the number of points on a central star shape increases by one (e.g., 4-point, 5-point, 6-point). Rule 2, applied down the columns from top to bottom, is that the star is enclosed by a shape that cycles from a circle, to a square, to a triangle. If the top-left cell contains a 4-point star inside a circle, what is the figure in the bottom-right cell?

Answer: A 6-point star inside a triangle

The bottom-right cell is in the third row and third column. According to the column rule (Rule 2), the enclosing shape in the third row must be a triangle (circle -> square -> triangle). According to the row rule (Rule 1), the star in the third column must have 6 points (4-point -> 5-point -> 6-point). Combining these rules, the correct figure is a 6-point star inside a triangle.

A 3x3 matrix follows two patterns. The pattern for each row dictates that the central object rotates 45 degrees clockwise in each subsequent cell. The pattern for each column dictates that the number of dots surrounding the central object increases by one. If the top-left cell shows an upright capital letter 'T' with one dot, what does the middle cell (row 2, column 2) contain?

Answer: A 'T' rotated 45 degrees clockwise with two dots

To find the figure in row 2, column 2, we can follow the rules from the top-left cell. Moving down to row 2, the number of dots increases from one to two. Moving right to column 2, the 'T' rotates 45 degrees clockwise. Therefore, the middle cell must contain a 'T' rotated 45 degrees clockwise and surrounded by two dots.

Which of the following scenarios best demonstrates the principle of simultaneous rule application in a Raven's Progressive Matrices problem?

Answer: A scenario where moving across a row adds a vertical line to the figure, and moving down a column adds a horizontal line to the figure.

Simultaneous rule application requires at least two distinct rules operating concurrently, typically with one rule governing the horizontal progression and another governing the vertical progression. The correct option describes exactly this: one rule for the rows (add a vertical line) and a separate, independent rule for the columns (add a horizontal line). The other options describe single-rule transformations.

Consider a 3x3 matrix where each cell contains a 2x2 grid. Two rules determine which squares are shaded. Rule 1 (for rows): The starting position of the shaded block(s) moves one position clockwise from cell to cell (Top-Left -> Top-Right -> Bottom-Right). Rule 2 (for columns): The number of shaded squares increases by one as you move down (Row 1 has one, Row 2 has two, Row 3 has three). If the top-left cell has only the top-left square shaded, what does the bottom-right cell look like?

Answer: A grid with the bottom-right, bottom-left, and top-left squares shaded.

The bottom-right cell is in Row 3 and Column 3. According to Rule 2, all cells in Row 3 must have three shaded squares. According to Rule 1, the starting position for shading in Column 3 is the bottom-right square (since C1 starts at TL, C2 at TR, C3 must start at BR). Therefore, the figure must have three squares shaded, starting from the bottom-right and proceeding clockwise, resulting in the bottom-right, bottom-left, and top-left squares being shaded.

In a 3x3 matrix, the main figure is a large arrow. Two properties of the arrow change. Horizontally, the arrow's fill pattern cycles between solid, hollow, and striped. Vertically, the arrow rotates 90 degrees counter-clockwise. Given the top-right cell contains a solid arrow pointing down, and the middle-left cell (row 2, column 1) contains a hollow arrow pointing right, what is the figure in the bottom-left cell (row 3, column 1)?

Answer: A hollow arrow pointing left

First, let's determine the orientation. The vertical rule is a 90-degree counter-clockwise rotation. Since the arrow in row 2, column 1 points right, the arrow in row 3, column 1 must point left. Next, let's determine the fill. The horizontal rule is a cycle. We are given that row 2, column 1 is hollow and row 1, column 3 is solid. This implies the cycle across the rows is hollow -> striped -> solid. Therefore, all figures in the first column must be hollow. Combining these two deductions, the figure in the bottom-left cell is a hollow arrow pointing left.

A 3x3 matrix operates on two rules. Rule 1 (rows): The number of identical elements increases by one (1, 2, 3). Rule 2 (columns): The orientation of all elements in the cell rotates 45 degrees counter-clockwise from the cell above. If the top-left cell contains one horizontal line and the cell to its right contains two horizontal lines, what is the figure in the bottom-right cell?

Answer: Three vertical lines

The target cell is in row 3, column 3. According to Rule 1 (rows), the number of elements in the third column must be three. According to Rule 2 (columns), the orientation rotates 45 degrees counter-clockwise down the column. Starting with a horizontal line in row 1, the elements in row 2 would be diagonal (rotated 45 degrees), and the elements in row 3 would be vertical (rotated another 45 degrees). Therefore, the bottom-right cell must contain three vertical lines.