Ramsay Test Time Management & Efficiency 6

Question 1

A maintenance technician has four work orders due today: (1) a leaking hydraulic line on a press running at 40% capacity, (2) a burned-out overhead light in a storage room, (3) a conveyor belt that makes noise but runs normally, and (4) an air compressor whose pressure relief valve chattered once but hasn't repeated. Which sequence best reflects industrial time-management principles?

Accepted Answer

1 → 4 → 3 → 2

Answer

The hydraulic leak (1) is both a safety hazard and an active production loss — it must come first. The pressure-relief valve chattering (4) is a potential catastrophic-failure precursor and ranks second even though it hasn't repeated, because pressure-system failures can be sudden and severe. The noisy conveyor (3) is a developing fault but currently operational, so it's third. The storage-room light (2) has no safety or production impact and goes last. Option A incorrectly promotes the conveyor over the pressure-system anomaly.

Question 2

During a planned 8-hour shutdown, a technician estimates: bearing replacement = 2 h, coupling alignment = 1.5 h, lubrication of 12 points = 45 min, and filter replacement = 30 min. The coupling alignment cannot begin until the bearing is fully seated and torqued. All other tasks are independent. What is the minimum possible completion time if one additional qualified technician is available for the entire window?

Accepted Answer

3.5 hours

Answer

The critical path is bearing replacement (2 h) → coupling alignment (1.5 h) = 3.5 h total, and this chain cannot be parallelized. The second technician can absorb lubrication (45 min) and filter replacement (30 min) — both finish well within the 3.5 h window. Therefore the bottleneck remains the serial bearing-then-alignment chain at 3.5 hours. Adding more technicians cannot compress this path further.

Question 3

A plant switches from a purely reactive maintenance program to condition-based monitoring on its ten most critical machines. In the first year, total downtime hours drop 28%, but total labor hours *increase* 12%. Which conclusion is best supported by these numbers?

Accepted Answer

The program is likely cost-effective because prevented downtime losses typically exceed added monitoring labor costs.

Answer

Unplanned downtime on critical equipment typically costs many times more per hour than planned maintenance labor (lost production, emergency parts premiums, overtime). A 28% reduction in downtime hours almost always far outweighs a 12% rise in scheduled labor hours. The data pattern — less downtime, more proactive labor — is exactly what a successful CBM transition looks like in year one. Concluding the program is inefficient from labor hours alone ignores the far larger cost of downtime.

Question 4

A technician is halfway through replacing a pump impeller when she discovers the replacement part has a slightly different shaft diameter than spec. The pump feeds a non-critical cooling tower. Shift ends in 90 minutes; sourcing the correct part will take ~4 hours. Which action best balances time management and plant safety?

Accepted Answer

Reassemble the pump with the original worn impeller, tag the system as 'repair pending,' document findings, and notify the next shift supervisor.

Answer

When a correct part is unavailable mid-job, the safest and most professional course is to restore the equipment to a known (if degraded) state, clearly tag it, document the discrepancy and part number needed, and hand off to the incoming shift. This keeps the system in a defined condition, preserves situational awareness across shifts, and avoids the hidden failures that come from force-fitting incorrect components. Options A and D introduce unquantified mechanical risk; option C creates an undocumented hazard.

Question 5

A maintenance planner is building next week's schedule and notices that three separate PMs (each ~2 hours) are due on machines A, B, and C in the same production cell. The cell runs Monday–Thursday; Friday is a light-production day. Completing all three PMs mid-week requires pulling technicians from two other cells during peak hours. What scheduling approach minimizes total production impact?

Accepted Answer

Batch all three PMs on Friday during light production and coordinate a single cell-access window.

Answer

Batching maintenance tasks in the same production cell into a single planned window minimizes the number of production interruptions and reduces technician travel/setup time. Friday's light production provides the lowest-impact window. Spreading PMs across three peak-production days (B) multiplies disruptions. Monday morning (A) hits peak production. Deferring PMs (D) accumulates risk and is only appropriate when overdue intervals remain within safe tolerance — the question doesn't support that assumption.

Ramsay Test Practice Test

Ramsay Test Practice Test

Ramsay Test Time Management & Efficiency 6