PS Traverse & Leveling Calculations 5

Question 1

In the DMD method, the Double Meridian Distance of the SECOND course equals:

Accepted Answer

DMD of first course + departure of first course + departure of second course

Answer

The propagation rule is: DMDₙ = DMDₙ₋₁ + Depₙ₋₁ + Depₙ; for the second course this equals DMD₁ + Dep₁ + Dep₂.

Question 2

In the DMD area method, 2A (double area) for the entire traverse equals:

Accepted Answer

The absolute value of Σ(Latitude × DMD) for all courses

Answer

The DMD method yields 2A = |Σ(Lat × DMD)|; divide by 2 for the actual area of the traverse.

Question 3

Stadia tacheometry uses the rod intercept (top wire minus bottom wire reading) and a stadia constant (typically 100) to determine:

Accepted Answer

Horizontal distance from instrument to rod

Answer

Horizontal distance = K × rod intercept × cos²(vertical angle), where K is the stadia interval factor (usually 100).

Question 4

Trigonometric leveling computes the elevation difference between instrument station and target as:

Accepted Answer

Δh = D·tan(α) + HI − RR

Answer

Trigonometric leveling: Δh = D·tan(α) + HI − RR, where D is horizontal distance, α is vertical angle, HI is instrument height, RR is rod/reflector height.

Question 5

A leveling loop of 12 km total length has a misclosure of 18 mm. Third-order leveling allows 12 mm√K (K in km). Does this loop meet the standard?

Accepted Answer

Yes — allowable = 41.6 mm; 18 mm < 41.6 mm so it passes

Answer

Allowable misclosure = 12 mm × √12 ≈ 41.6 mm; since 18 mm < 41.6 mm, the loop meets third-order standards.

(PS) Professional Licensed Surveyor Practice Test

(PS) Professional Licensed Surveyor Practice Test

PS Traverse & Leveling Calculations 5