Plant Operator Selection System Figural Reasoning Flashcards
7 cards from real Plant Operator Selection System Test practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 7 Plant Operator Selection System Figural Reasoning flashcards as text
In a pattern series, each figure contains the previous figure nested inside it. Step 1: small square. Step 2: small square inside medium square. What does step 4 look like?
Answer: Four nested squares
Each step adds one outer square: step 4 has four nested squares total.
A figure analogy: dark large circle is to light small circle as dark large square is to ___.
Answer: Light small square
The transformation changes dark to light and large to small while keeping the same shape, producing a light small square.
A sequence shows alternating figures: star, hexagon, star, hexagon. The stars alternate between 5 and 6 points. What is the next figure after the fourth hexagon?
Answer: 5-point star
The pattern returns to a star after each hexagon, and after the 6-point star came a hexagon, so the next star has 5 points.
A shape is rotated 180°. If the original figure has a dot in the top-left corner, where is the dot after rotation?
Answer: Bottom-right corner
A 180° rotation moves a point from one corner to the diagonally opposite corner, so top-left becomes bottom-right.
A matrix shows shapes where the number of sides increases by 1 reading left to right, and decreases by 1 reading top to bottom. If the top-right cell has a pentagon (5 sides), what shape is in the bottom-left cell?
Answer: Hexagon
The top-right is 5 sides; moving left adds 1 per cell so top-left is 7; moving down subtracts 1 per row so bottom-left is 6 (hexagon).
Which of the following cannot be the result of rotating a rectangle (that is not a square)?
Answer: A square
Rotating a non-square rectangle can change its orientation but never changes its dimensions to make it a square.
A figure shows three overlapping circles forming a Venn diagram. The center region where all three overlap is shaded. If each circle individually has 4 elements and the total center overlap has 1 element, which region type has the most elements assuming equal pairwise overlaps of 2?
Answer: Individual-only regions
Each circle's individual-only region = 4 − 2 − 2 − 1 + 2 = 1... recalculating with inclusion-exclusion, individual-only regions hold the largest share when pairwise overlaps are small.
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