An optician uses a lens clock to measure the front surface of a lens and gets a reading of +6.50 D. The back surface measures -6.00 D in one meridian and -8.00 D in the perpendicular meridian. Assuming the lens clock is calibrated for the lens material, what is the nominal power of this lens?
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A
+0.50 -2.00 x 090
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B
+0.50 -2.00 x 180
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C
-1.50 +2.00 x 090
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D
-1.50 -2.00 x 180