Engineering Economics Flashcards
7 cards from real NCEES practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 7 Engineering Economics flashcards as text
A machine costs $50,000 and has a salvage value of $5,000 after 10 years. Using straight-line depreciation, what is the annual depreciation charge?
Answer: $4,500
Straight-line depreciation = (Cost − Salvage) / Life = ($50,000 − $5,000) / 10 = $4,500/year.
What is the benefit-cost ratio of a project with a present worth of benefits of $120,000 and a present worth of costs of $80,000?
Answer: 1.50
BCR = PW(Benefits) / PW(Costs) = $120,000 / $80,000 = 1.50.
An investment has cash flows of $10,000/year for 5 years. At i = 8%, what is the present worth using the uniform series present worth factor (P/A, 8%, 5) = 3.9927?
Answer: $39,927
PW = A × (P/A, i, n) = $10,000 × 3.9927 = $39,927.
Which depreciation method results in the largest depreciation deduction in the first year for most assets?
Answer: Double declining balance
Double declining balance applies twice the straight-line rate to the book value, producing the largest first-year deduction.
A company borrows $100,000 at 6% annual interest compounded monthly. What is the effective annual interest rate?
Answer: 6.168%
EAR = (1 + 0.06/12)^12 − 1 = (1.005)^12 − 1 ≈ 6.168%.
If a project has a net present value of zero, which of the following is true?
Answer: The project's IRR equals the MARR
NPV = 0 means the project's return exactly equals the discount rate (MARR), making IRR = MARR.
Two mutually exclusive alternatives are compared using present worth analysis. Alternative A has PW = $15,000 and Alternative B has PW = $22,000. What is the correct decision?
Answer: Select Alternative B
In present worth analysis, select the alternative with the highest positive net present worth, which is Alternative B.
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