NBT NBT Mathematics: Functions and Graphs 2

Question 1

The graph of y = ax + b passes through (0, 4) and (2, 0). What are the values of a and b?

Accepted Answer

a = −2, b = 4

Answer

y-intercept gives b = 4; gradient = (0 − 4) ÷ (2 − 0) = −2, so a = −2.

Question 2

Which of the following is the equation of a parabola with vertex at (2, −3) and passing through (0, 1)?

Accepted Answer

y = (x − 2)² − 3

Answer

Vertex (2, −3) gives y = a(x − 2)² − 3. Substituting (0, 1): 1 = 4a − 3 → a = 1. So y = (x − 2)² − 3.

Question 3

The function p(x) = 2^x. The graph of q(x) is p(x) shifted 3 units upward. What is q(x)?

Accepted Answer

q(x) = 2^x + 3

Answer

A vertical shift of 3 units upward adds 3 to the function: q(x) = 2^x + 3.

Question 4

The domain of f(x) = √(x − 5) is:

Accepted Answer

x ≥ 5

Answer

The expression under the square root must be ≥ 0: x − 5 ≥ 0 → x ≥ 5.

Question 5

A graph shows f(x) crossing the x-axis at x = −3 and x = 2, with a y-intercept at y = −6. Which function fits?

Accepted Answer

f(x) = (x + 3)(x − 2)

Answer

Roots at −3 and 2 → f(x) = a(x + 3)(x − 2). At x = 0: a(3)(−2) = −6 → −6a = −6 → a = 1.

(NBT) National Benchmark Test Practice Test