Solve: $\sqrt{2x + 3} = 5$

Squaring both sides: $2x + 3 = 25$, so $x = 11$.

Expand and simplify: $(\sqrt{5} + \sqrt{2})(\sqrt{5} - \sqrt{2})$

Using difference of squares: $(\sqrt{5})^2 - (\sqrt{2})^2 = 5 - 2 = 3$.

Factorising: $x(x-7) = 0$, so $x = 0$ or $x = 7$.

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Which of the following equals $16^{-3/4}$?