Mettl Numerical Reasoning 2 — Questions and Answers
Question 1: A company's revenue grew from ₹40 lakh to ₹52 lakh. What is the percentage growth?
- 25%
- 30% (Correct answer)
- 20%
- 35%
Correct answer: 30%
Growth = 52-40 = 12 lakh. Percentage growth = (12/40) × 100 = 30%.
Percentage growth formula: % Growth = [(New Value - Original Value) / Original Value] × 100. Calculation: Change = 52 - 40 = ₹12 lakh. % Growth = (12/40) × 100 = 0.30 × 100 = 30%. Verify: 40 × 1.30 = 52 ✓. Common mistake: dividing by the new value (12/52 = 23%) — always divide by the original. Mettl numerical reasoning tests for business and analytical roles heavily test percentage calculations with financial data.
Question 2: If a product costs ₹1,200 after a 25% discount, what was the original price?
- ₹1,500
- ₹1,600 (Correct answer)
- ₹1,400
- ₹1,800
Correct answer: ₹1,600
₹1,200 = 75% of original price. Original = 1200/0.75 = ₹1,600.
Reverse percentage problems: If ₹1,200 is the price after a 25% discount, then ₹1,200 represents (100% - 25%) = 75% of the original price. Original price = 1200 ÷ 0.75 = ₹1,600. Verify: 25% of 1600 = ₹400 discount. 1600 - 400 = ₹1,200 ✓. A common mistake is adding 25% to ₹1,200 (= ₹1,500) — this incorrectly takes 25% of the discounted price, not the original. Mettl numerical reasoning tests frequently include reverse percentage problems for roles requiring financial analysis.
Question 3: A company has 240 employees. 35% work in operations, 25% in sales, 20% in IT, and the rest in admin. How many employees work in admin?
- 40
- 48 (Correct answer)
- 36
- 60
Correct answer: 48
Admin = 100% - 35% - 25% - 20% = 20%. 20% of 240 = 48.
Step 1: Find the admin percentage. Operations (35%) + Sales (25%) + IT (20%) = 80%. Admin = 100% - 80% = 20%. Step 2: Calculate the number. 20% of 240 = (20/100) × 240 = 0.20 × 240 = 48 employees. Verify: 84 + 60 + 48 + 48 = 240 ✓. This type of workforce distribution problem appears regularly in Mettl numerical reasoning tests for HR, business operations, and management roles.
Question 4: What is the simple interest on ₹8,000 at 6% per annum for 3 years?
- ₹1,200
- ₹1,440 (Correct answer)
- ₹1,680
- ₹960
Correct answer: ₹1,440
SI = (P × R × T) / 100 = (8000 × 6 × 3) / 100 = 144000/100 = ₹1,440.
Simple Interest (SI) formula: SI = (P × R × T) / 100. Where P = Principal (₹8,000), R = Rate per annum (6%), T = Time in years (3). Calculation: SI = (8000 × 6 × 3) / 100 = 144,000 / 100 = ₹1,440. Total amount after 3 years = P + SI = 8000 + 1440 = ₹9,440. Compare with compound interest (same values): CI = 8000(1.06)³ - 8000 = 9,528.13 - 8000 = ₹1,528.13. The difference of ₹88.13 is the 'interest on interest' in compound calculation. Mettl numerical assessments for banking and finance roles test both SI and CI formulas.
Question 5: Three numbers are in the ratio 2:3:5. Their sum is 200. What is the largest number?
- 80
- 100 (Correct answer)
- 60
- 120
Correct answer: 100
Total ratio parts = 2+3+5 = 10. Largest share = 5/10 of 200 = 100.
Ratio partition: Total ratio parts = 2+3+5 = 10. Each part = 200/10 = 20. The three numbers: smallest = 2×20 = 40, middle = 3×20 = 60, largest = 5×20 = 100. Verify: 40+60+100 = 200 ✓. The ratio 2:3:5 is maintained: 40:60:100 simplifies to 2:3:5 (divide by 20) ✓. Ratio and proportion questions are fundamental in Mettl numerical reasoning sections for business, engineering, and analytical roles.
Question 6: A car depreciates at 15% per year. If it costs ₹6,00,000 today, what will be its value after 2 years?
- ₹4,25,000
- ₹4,33,500 (Correct answer)
- ₹4,20,000
- ₹4,50,000
Correct answer: ₹4,33,500
After 2 years: Value = 600000 × (1-0.15)² = 600000 × 0.85² = 600000 × 0.7225 = ₹4,33,500.
Depreciation formula: V = P(1 - r)^n where P = initial value, r = depreciation rate, n = years. Year 1: 600,000 × 0.85 = ₹5,10,000. Year 2: 510,000 × 0.85 = ₹4,33,500. Or directly: 600,000 × 0.85² = 600,000 × 0.7225 = ₹4,33,500. Note: Each year's depreciation is calculated on the previous year's value (like compound interest in reverse), not on the original value. This is different from straight-line depreciation (fixed amount each year). Mettl numerical reasoning tests for finance and accounting roles frequently include depreciation calculations.
A company's revenue grew from ₹40 lakh to ₹52 lakh.
What is the percentage growth?