LSIT Mathematics for Surveying 5

Question 1

The tangent length (T) of a simple circular curve with radius R = 600 ft and central angle Δ = 38°20' is closest to:

Accepted Answer

208.8 ft

Answer

T = R × tan(Δ/2) = 600 × tan(19°10') = 600 × 0.34730 ≈ 208.8 ft.

Question 2

A surveyor uses a total station to measure an azimuth of 214°33' to a target. What is the equivalent bearing?

Accepted Answer

S 34°33' W

Answer

Azimuths between 180° and 270° are in the SW quadrant; bearing = azimuth − 180° = 214°33' − 180° = S 34°33' W.

Question 3

In differential leveling, a backsight of 8.213 ft is taken on a benchmark (elev = 504.127 ft) and a foresight of 2.645 ft is taken on the next point. What is the elevation of the next point?

Accepted Answer

509.695 ft

Answer

HI = 504.127 + 8.213 = 512.340 ft; Elev = 512.340 − 2.645 = 509.695 ft.

Question 4

A rectangular parcel measures 330.0 ft × 660.0 ft. How many acres does it contain?

Accepted Answer

5.0 acres

Answer

Area = 330.0 × 660.0 = 217,800 sq ft; 217,800 / 43,560 = 5.0 acres.

Question 5

Using the Pythagorean theorem, if the northing difference between two points is 315.62 ft and the easting difference is 248.17 ft, the horizontal distance is approximately:

Accepted Answer

401.5 ft

Answer

Distance = √(315.62² + 248.17²) = √(99,616 + 61,588) = √161,204 ≈ 401.5 ft.

(LSIT) Land Surveyor in Training Practice Test

(LSIT) Land Surveyor in Training Practice Test

LSIT Mathematics for Surveying 5