LSIT Mathematics for Surveying 3

Question 1

A slope distance of 542.30 ft is measured on a grade of 3.75%. What is the horizontal distance?

Accepted Answer

541.91 ft

Answer

Horizontal distance = slope distance × cos(arctan(0.0375)) ≈ 542.30 × 0.99930 ≈ 541.91 ft.

Question 2

The interior angles of a closed five-sided traverse sum to 540°. If four measured angles are 98°14', 112°33', 87°47', and 125°06', what is the fifth angle (assuming no angular error)?

Accepted Answer

116°20'

Answer

Sum of four angles = 423°40'; fifth angle = 540°00' − 423°40' = 116°20'.

Question 3

Using the coordinate method, a triangle has vertices at (0,0), (6,0), and (3,4). What is its area in square units?

Accepted Answer

12

Answer

Area = ½|x₁(y₂−y₃)+x₂(y₃−y₁)+x₃(y₁−y₂)| = ½|0(0−4)+6(4−0)+3(0−0)| = ½×24 = 12.

Question 4

A surveyor needs to convert 45°27'36" to decimal degrees. What is the result?

Accepted Answer

45.460°

Answer

27'/60 = 0.450°; 36"/3600 = 0.010°; total = 45 + 0.450 + 0.010 = 45.460°.

Question 5

A circular curve has a radius of 800 ft and a central angle (Δ) of 24°30'. What is the arc length?

Accepted Answer

341.75 ft

Answer

Arc length = R × Δ (radians) = 800 × (24.5° × π/180) = 800 × 0.42760 ≈ 341.75 ft.

(LSIT) Land Surveyor in Training Practice Test

(LSIT) Land Surveyor in Training Practice Test

LSIT Mathematics for Surveying 3