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Mathematics and Geomatics Flashcards

7 cards from real LSIT practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 Mathematics and Geomatics flashcards as text
  1. A horizontal curve has a radius of 1,200 ft and a central angle (Δ) of 24°30'. The tangent length T equals:

    Answer: 261.5 ft

    T = R × tan(Δ/2) = 1200 × tan(12°15') = 1200 × 0.2174 ≈ 261.5 ft.

  2. The relationship between geodetic height (h), orthometric height (H), and geoid undulation (N) is:

    Answer: h = H + N

    Geodetic (ellipsoidal) height h equals orthometric height H plus geoid undulation N: h = H + N.

  3. A closed traverse has 5 sides. The sum of interior angles should equal:

    Answer: 540°

    Sum of interior angles = (n - 2) × 180° = (5 - 2) × 180° = 540°.

  4. In coordinate geometry (COGO), the inverse computation determines:

    Answer: Distance and bearing between two known coordinate pairs

    The inverse problem computes direction (bearing/azimuth) and distance from the coordinates of two known points.

  5. The scale factor in a State Plane Coordinate System (SPCS) is applied to account for:

    Answer: The difference between grid distances on the projection plane and geodetic distances on the ellipsoid

    The grid scale factor converts ellipsoidal geodetic distances to grid (plane) distances used in SPCS computations.

  6. A surveyor uses a total station that measures slope distance as 487.34 ft at a vertical angle of +5°22'. The horizontal distance is approximately:

    Answer: 485.51 ft

    HD = SD × cos(vertical angle) = 487.34 × cos(5°22') = 487.34 × 0.9956 ≈ 485.51 ft.

  7. In photogrammetry, the principal distance (c) of a camera is most accurately defined as:

    Answer: The perpendicular distance from the rear nodal point of the lens to the image plane

    Principal distance (calibrated focal length) is the distance from the rear nodal point to the principal point on the image plane, determined by calibration.

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