PSAT Algebra & Functions 1

Question 1

What is the solution to the equation 2x + 5 = 11?

Accepted Answer

x = 3

Answer

To solve the equation 2x + 5 = 11, first subtract 5 from both sides of the equation, which gives 2x = 6. Then, divide both sides by 2 to isolate x. This results in x = 3, which is the correct solution.

Question 2

What is the value of x in the equation x^2 = 16?

Accepted Answer

x = 4 or x = -4

Answer

To find the value of x in the equation x^2 = 16, you need to take the square root of both sides. Remember that a positive number has two square roots: a positive one and a negative one. Therefore, both 4 (since 4*4=16) and -4 (since -4*-4=16) are valid solutions for x.

Question 3

What is the slope of the line represented by the equation y = 3x + 2?

Accepted Answer

Slope = 3

Answer

The equation y = 3x + 2 is in the slope-intercept form, which is y = mx + b. In this standard form, 'm' represents the slope of the line and 'b' represents the y-intercept. Therefore, by direct comparison, the coefficient of x, which is 3, is the slope of the line.

Question 4

What is the solution to the equation 3(x + 2) = 18?

Accepted Answer

x = 4

Answer

To solve the equation 3(x + 2) = 18, first divide both sides by 3, which simplifies the equation to x + 2 = 6. Next, subtract 2 from both sides of the equation to isolate x. This operation yields x = 4 as the solution.

Question 5

What is the value of y when x = 2 in the equation y = 2x + 3?

Accepted Answer

y = 7

Answer

To find the value of y when x = 2 in the equation y = 2x + 3, simply substitute the value of x into the equation. This gives y = 2(2) + 3. Performing the multiplication first, y = 4 + 3, which simplifies to y = 7.

PSAT/NMSQT Practice Test

PSAT/NMSQT Practice Test

PSAT Algebra & Functions 1