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Survey Calculations & Coordinate Systems Flashcards

7 cards from real CST practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 Survey Calculations & Coordinate Systems flashcards as text
  1. Point A is at N 1000.00, E 1000.00 and Point B is at N 1300.00, E 1400.00. What is the inverse distance from A to B?

    Answer: 500.00 ft

    Distance = √(300² + 400²) = 500.00 ft.

  2. For the same line from A (N 1000, E 1000) to B (N 1300, E 1400), what is the bearing?

    Answer: N 53°07'48" E

    Bearing angle = arctan(ΔE/ΔN) = arctan(400/300) = 53°07'48", and both ΔN and ΔE are positive, so the line runs NE.

  3. How many acres are in a parcel of 87,120 square feet?

    Answer: 2.00 acres

    One acre is 43,560 sq ft, so 87,120 / 43,560 = 2.00 acres.

  4. A circular curve has a radius of 1,000.00 ft and a central angle of 60°. What is the arc length?

    Answer: 1,047.20 ft

    L = R × Δ × π/180 = 1000 × 60 × π/180 = 1,047.20 ft.

  5. For a curve with R = 1,000.00 ft and Δ = 60°, what is the tangent length T?

    Answer: 577.35 ft

    T = R × tan(Δ/2) = 1000 × tan 30° = 577.35 ft.

  6. Using the arc definition, what is the degree of curve for a radius of 1,000.00 ft?

    Answer: 5°43'46"

    D = 5729.58 / R = 5.7296° ≈ 5°43'46".

  7. A total station measures a slope distance of 300.00 ft at a zenith angle of 85°00'. What is the horizontal distance?

    Answer: 298.86 ft

    Horizontal distance = slope distance × sin(zenith) = 300 × sin 85° = 298.86 ft.