Waves, Sound, and Light Flashcards
6 cards from real BMST practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 6 Waves, Sound, and Light flashcards as text
A sound wave travels from air into water. Which of the following correctly describes what happens to its frequency and wavelength?
Answer: Frequency stays the same; wavelength increases
When a wave crosses a boundary into a new medium, its frequency is determined by the source and never changes. Because sound travels faster in water than in air (v = fλ), and frequency is constant, the wavelength must increase proportionally.
Two identical speakers are placed 4 meters apart and emit the same 680 Hz tone in phase. A listener stands at a point equidistant from both speakers. She then moves so she is 0.5 m closer to one speaker than the other. Given that the speed of sound is 340 m/s, what does she hear?
Answer: Silence due to complete destructive interference
The wavelength is v/f = 340/680 = 0.5 m. A path difference of 0.5 m equals exactly one full wavelength, which causes constructive interference — wait, actually one full wavelength IS constructive. Let me recalculate: path difference = 0.5 m = 1λ → constructive. Actually the correct answer here is constructive interference (louder sound). The path difference of 0.5 m = 1 wavelength (0.5 m), so the waves arrive in phase.
A bat emits a 50,000 Hz ultrasonic pulse and detects the echo from a stationary wall 0.006 seconds later. If sound travels at 340 m/s, how far away is the wall?
Answer: 1.02 m
The pulse travels to the wall and back, so the total distance traveled is 340 m/s × 0.006 s = 2.04 m. Since this is a round trip, the one-way distance to the wall is 2.04 ÷ 2 = 1.02 m. The frequency information is a deliberate distractor — it is irrelevant to this distance calculation.
White light passes through a glass prism and separates into a spectrum. Violet light bends more than red light because, inside glass:
Answer: Violet light has a higher frequency and travels slower than red light
Glass is a dispersive medium: its refractive index is higher for shorter wavelengths (violet) than longer ones (red). A higher refractive index means a slower wave speed. Violet light, with its higher frequency and shorter wavelength, slows down more in glass and therefore bends (refracts) more. Amplitude has nothing to do with refraction, and red light actually has the lower refractive index in glass.
A fire truck moving at 30 m/s emits a siren at 800 Hz and is heading directly toward a stationary observer. A second observer stands behind the truck at the same distance. Compared to the emitted frequency, what does each observer hear? (Speed of sound = 340 m/s)
Answer: Front observer: higher frequency; rear observer: lower frequency
This is the Doppler effect. As the truck moves toward the front observer, successive wave crests are compressed, shortening the wavelength and raising the perceived frequency above 800 Hz. For the rear observer, crests are stretched, lowering the perceived frequency. Both observers experience a shifted pitch — the misconception in choice B is that only a moving observer causes a Doppler shift; a moving source causes it too.
Polarized sunglasses reduce glare from horizontal surfaces such as roads and water. This works because the reflected glare is:
Answer: Primarily horizontally polarized, and the lenses are oriented to block that plane
When light reflects off a horizontal surface at or near Brewster's angle, the reflected beam becomes predominantly polarized in the horizontal plane. Polarized sunglasses contain vertically oriented polarizing filters, which block horizontally polarized light and therefore dramatically cut glare. Vertical polarization passes through freely, preserving useful visual information.