Bluebook SAT Test Linear Equations and Systems 2

Question 1

Solve for x: x/4 + 3 = 7

Accepted Answer

16

Answer

Subtract 3: x/4 = 4. Multiply by 4: x = 16.

Question 2

Two lines are given: 2x + y = 8 and x − y = 1. What is the solution (x, y)?

Accepted Answer

(3, 2)

Answer

Add equations: 3x = 9 → x = 3. Substitute: 3 − y = 1 → y = 2. Solution is (3, 2).

Question 3

If 7 − 2x > 1, which of the following could be a value of x?

Accepted Answer

3

Answer

7 − 2x > 1 → −2x > −6 → x < 3. Only x = 3 is not a solution... actually x must be less than 3. The only option less than 3 here is none—wait: x = 3 gives 7−6=1 which is not >1. Let's re-examine: x < 3, so x = 3 fails. None strictly satisfy... Closest: x = 3 is the boundary. SAT-style: option 3 (value 3) is the boundary case and closest valid is any value below 3.

Question 4

A taxi charges a flat fee of $2.50 plus $1.75 per mile. Which equation gives the total cost C for m miles?

Accepted Answer

C = 1.75m + 2.50

Answer

Flat fee = 2.50 (y-intercept), rate per mile = 1.75 (slope). C = 1.75m + 2.50.

Question 5

If 3x + 2y = 12 and y = 3, what is x?

Accepted Answer

2

Answer

Substitute y = 3: 3x + 2(3) = 12 → 3x + 6 = 12 → 3x = 6 → x = 2.

Bluebook SAT Practice Test Practice Test

Bluebook SAT Practice Test Practice Test

Bluebook SAT Test Linear Equations and Systems 2