SAT Exponents and Radicals Practice Flashcards
28 cards from real Bluebook SAT Test practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 20 SAT Exponents and Radicals Practice flashcards as text
Which of the following is equivalent to x^(2/3)?
Answer: ∛(x²)
The rational exponent 2/3 means the cube root of x squared: x^(2/3) = ∛(x²).
Simplify: (3x²y³)² × (2xy)³
Answer: 72x⁷y⁹
(3x²y³)² = 9x⁴y⁶ and (2xy)³ = 8x³y³. Product = 72x^(4+3)y^(6+3) = 72x⁷y⁹.
What is the value of 27^(−2/3)?
Answer: 1/9
27^(2/3) = (∛27)² = 3² = 9. The negative exponent gives the reciprocal: 1/9.
If 2^x = 32, what is the value of 2^(x−3)?
Answer: 4
2^x = 2^5 so x = 5. Then 2^(5−3) = 2² = 4.
Simplify: √(50x⁴y²)
Answer: 5x²y√2
√(50x⁴y²) = √(25·2·x⁴·y²) = 5x²y√2.
Which expression is equivalent to (x^(1/2))(x^(1/3))?
Answer: x^(5/6)
Add exponents: 1/2 + 1/3 = 3/6 + 2/6 = 5/6. Result is x^(5/6).
What is the value of (8^(1/3) + 16^(1/2)) ÷ 4^(1/2)?
Answer: 3
8^(1/3) = 2, 16^(1/2) = 4, 4^(1/2) = 2. (2 + 4)/2 = 3.
Which of the following equals 3^(x+2)?
Answer: 9 × 3^x
3^(x+2) = 3^x × 3² = 9 × 3^x.
Simplify ∛54 in simplest radical form.
Answer: 3∛2
∛54 = ∛(27 × 2) = 3∛2.
What is the value of x if √(x + 9) − √x = 1?
Answer: 16
Isolate: √(x+9) = √x + 1. Square: x + 9 = x + 2√x + 1 → 8 = 2√x → √x = 4 → x = 16.
Simplify: (x²/y)³ ÷ (x/y²)²
Answer: x⁴y
(x²/y)³ = x⁶/y³ and (x/y²)² = x²/y⁴. Dividing: x⁶/y³ ÷ x²/y⁴ = x⁴y.
Which of the following equals 5^(1/2) × 20^(1/2)?
Answer: 10
(5 × 20)^(1/2) = 100^(1/2) = 10.
Determine the value of (−32)^(3/5).
Answer: −8
(−32)^(3/5) = (⁵√(−32))³ = (−2)³ = −8.
Simplify: (a²b⁻¹)^3 × (a⁻¹b²)^2
Answer: a⁴b
(a²b⁻¹)³ = a⁶b^(−3) and (a⁻¹b²)² = a^(−2)b⁴. Product = a^(6−2)b^(−3+4) = a⁴b.
What is (2.5 × 10⁸) ÷ (5.0 × 10³) in scientific notation?
Answer: 5.0 × 10⁴
(2.5 ÷ 5.0) × 10^(8−3) = 0.5 × 10⁵ = 5.0 × 10⁴.
If f(x) = x^(2/3) and f(k) = 4, what is k?
Answer: 8
k^(2/3) = 4 → k = 4^(3/2) = (√4)³ = 8.
Which is greater: 2^30 or 3^20?
Answer: 3^20
2^30 = (2³)^10 = 8^10 and 3^20 = (3²)^10 = 9^10. Since 9 > 8, we have 3^20 > 2^30.
Simplify √(x² + 6x + 9) for x ≥ 0.
Answer: x + 3
x² + 6x + 9 = (x+3)². For x ≥ 0, x+3 > 0, so √((x+3)²) = x+3.
What is the simplified form of (27/8)^(2/3)?
Answer: 9/4
(27/8)^(2/3) = (∛(27/8))² = (3/2)² = 9/4.
Solve: 2^(3x−1) = 16
Answer: x = 5/3
16 = 2⁴, so 3x − 1 = 4 → x = 5/3.
How this page was made: written with AI tools and published by Nathan Beja, founder of Practice Test Geeks, who is responsible for its content. Exam facts are checked against the official sources listed below. Not reviewed by a subject-matter expert. Editorial policy
Sources & references
Exam facts on this page (fees, format, dates, passing scores) are checked against these official sources; the date is our last check. Editorial policy
- satsuite.collegeboard.org — Score release, test delivery, time limit, test dates, fees, registration, retake policy · verified Oct 2026
- bluebook.collegeboard.org — Test delivery · verified Oct 2026