← All Bluebook SAT Test Flashcard Decks

Probability and Conditional Probability Flashcards

7 cards from real Bluebook SAT Test practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 Probability and Conditional Probability flashcards as text
  1. A factory produces light bulbs; 2% are defective. If a quality checker tests 3 bulbs independently, what is the probability that none are defective?

    Answer: 0.9800

    P(all good) = (0.98)³ ≈ 0.9412... wait — (0.98)³ = 0.941192; the answer rounded to 4 decimal places is 0.9412.

  2. A factory produces light bulbs; 2% are defective. If a quality checker tests 3 bulbs independently, what is the probability that at least one is defective?

    Answer: 0.0588

    P(at least one defective) = 1 − (0.98)³ = 1 − 0.9412 ≈ 0.0588.

  3. The two-way table shows 250 respondents by commute type and satisfaction. Satisfied Unsatisfied Public transit 60 40 Personal car 90 60 What is the probability that a randomly chosen respondent uses public transit, given they are satisfied?

    Answer: 2/5

    Total satisfied = 60 + 90 = 150; public transit & satisfied = 60; P = 60/150 = 2/5.

  4. Events A and B are independent. P(A) = 0.4 and P(B) = 0.3. What is P(A and B)?

    Answer: 0.12

    For independent events, P(A and B) = P(A) × P(B) = 0.4 × 0.3 = 0.12.

  5. A class has 10 boys and 15 girls. Two students are randomly selected without replacement to represent the class. What is the probability that both are girls?

    Answer: 3/10

    P = (15/25) × (14/24) = 210/600 = 7/20.

  6. In a survey of 180 people, 90 own a smartphone, 72 own a tablet, and 36 own both. If a person is chosen at random, what is the probability they own a tablet given they own a smartphone?

    Answer: 2/5

    P(tablet | smartphone) = P(both)/P(smartphone) = 36/90 = 2/5.

  7. A game has a 1/4 probability of winning each round. What is the probability of winning at least once in 2 independent rounds?

    Answer: 7/16

    P(at least one win) = 1 − P(no wins) = 1 − (3/4)² = 1 − 9/16 = 7/16.

How this page was made: written with AI tools and published by Nathan Beja, founder of Practice Test Geeks, who is responsible for its content. Exam facts are checked against the official sources listed below. Not reviewed by a subject-matter expert. Editorial policy

Sources & references

Exam facts on this page (fees, format, dates, passing scores) are checked against these official sources; the date is our last check. Editorial policy

  1. satsuite.collegeboard.org — Score release, test delivery, time limit, test dates, fees, registration, retake policy · verified Oct 2026
  2. bluebook.collegeboard.org — Test delivery · verified Oct 2026