Proof Techniques Flashcards
7 cards from real TMUA practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 7 Proof Techniques flashcards as text
Which of the following best describes a 'non-constructive' existence proof?
Answer: It proves existence without identifying the object explicitly
A non-constructive proof establishes that something must exist (e.g. via contradiction) without providing an explicit example.
Prove or disprove: 'For all integers n, n² − n is even.' The correct conclusion is:
Answer: True; n² − n = n(n−1) is a product of consecutive integers
n(n−1) is a product of consecutive integers, so one factor is always even, making the product even.
Which rule of inference is: 'P ∨ Q, ¬P ⊢ Q'?
Answer: Disjunctive syllogism
Disjunctive syllogism eliminates one option in a disjunction when the other is known to be false.
In a proof by cases for an integer n, the usual split is n ≡ 0 (mod 2) and n ≡ 1 (mod 2). What guarantees these two cases are exhaustive?
Answer: Every integer is either even or odd (the division algorithm)
The division algorithm guarantees every integer has remainder 0 or 1 when divided by 2, covering all possibilities.
Why is 'proof by example' invalid for universal statements?
Answer: Both A and C
A single example demonstrates existence but cannot rule out counterexamples; universal proofs require an argument covering every case.
A student claims: 'Since 2+3=5 (prime), 4+3=7 (prime), and 6+3=9 is not prime, the pattern breaks.' This is an example of:
Answer: A counterexample disproving a conjecture
Finding 6+3=9 which is not prime provides a counterexample that disproves the conjecture that 'even + 3 is always prime'.
To prove: 'If x and y are both irrational, then x + y is irrational', a student attempts a direct proof. The attempt fails because:
Answer: The sum of two irrationals can be rational, e.g. √2 + (−√2) = 0
√2 + (−√2) = 0 ∈ ℚ is a counterexample showing the statement is false, so no valid proof exists.