Calculus Flashcards
7 cards from real TMUA practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 7 Calculus flashcards as text
The volume of the solid formed by rotating y = √x about the x-axis from x = 0 to x = 4 is:
Answer: 8π
V = π∫₀⁴ (√x)² dx = π∫₀⁴ x dx = π[x²/2]₀⁴ = 8π.
Which of the following is an antiderivative of 1/(1 + x²)?
Answer: arctan(x)
d/dx[arctan(x)] = 1/(1 + x²), so arctan(x) + C is the antiderivative.
Using implicit differentiation, find dy/dx if x² + y² = 25.
Answer: −x/y
Differentiating: 2x + 2y·(dy/dx) = 0, so dy/dx = −x/y.
lim_{h→0} [f(x+h) − f(x)]/h defines:
Answer: The derivative f′(x)
This is the limit definition of the derivative f′(x) at a point x.
f(x) = x⁴ − 8x² + 3 has local minima at:
Answer: x = 2 and x = −2
f′(x) = 4x(x² − 4) = 0 at x = 0, ±2; f″(±2) = 32 > 0 confirms minima at x = ±2.
The product rule for differentiating u(x)·v(x) gives:
Answer: u′·v + u·v′
The product rule states d/dx[u·v] = u′·v + u·v′.
∫ (2x + 3)⁵ dx = ?
Answer: (2x + 3)⁶/12 + C
With u = 2x + 3, du = 2 dx; ∫ u⁵ du/2 = u⁶/12 + C = (2x + 3)⁶/12 + C.