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Mechanical Comprehension Flashcards

7 cards from real TALENTLENS practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 Mechanical Comprehension flashcards as text
  1. A wheel with a radius of 2 ft is attached to a wheel with a radius of 4 ft. If the smaller wheel rotates at 60 RPM, how fast does the larger wheel rotate?

    Answer: 30 RPM

    Gear/wheel ratio: smaller turns at 60 RPM, larger is twice the radius, so it turns at 60 ÷ 2 = 30 RPM.

  2. A hydraulic jack has an input piston of 2 sq in and an output piston of 20 sq in. If you apply 50 lbs of force to the input, what output force is produced?

    Answer: 500 lbs

    Pascal's law: output force = (output area / input area) × input force = (20/2) × 50 = 500 lbs.

  3. Which type of beam deflects the least when a load is applied at its center?

    Answer: A shorter beam of the same material

    Shorter beams deflect less because deflection increases with the cube of the span length.

  4. A ball rolls down a frictionless ramp and onto a flat surface. What happens to its speed on the flat surface?

    Answer: It remains constant

    With no friction and no slope, there is no net force, so by Newton's first law the speed stays constant.

  5. A solid cylinder and a hollow cylinder of the same mass and outer radius roll down a ramp. Which reaches the bottom first?

    Answer: The solid cylinder

    The solid cylinder has a lower moment of inertia, so less energy goes into rotation and more into translation, making it faster.

  6. Two blocks connected by a rope over a frictionless pulley sit on a frictionless table. One block is pushed toward the pulley. What happens to the tension in the rope?

    Answer: Tension becomes zero

    If the block is pushed toward the pulley (slack rope), the rope goes slack and tension drops to zero.

  7. A wrench 12 inches long applies a torque of 60 ft-lbs. Approximately how much force is applied?

    Answer: 60 lbs

    Torque = Force × distance; 12 in = 1 ft, so Force = 60 ft-lbs ÷ 1 ft = 60 lbs.