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Physical Sciences Flashcards

7 cards from real STP practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

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  1. Which interaction is primarily responsible for the attenuation of low-energy X-rays (below ~30 keV) in soft tissue?

    Answer: Photoelectric effect

    At low photon energies, the photoelectric effect dominates because its cross-section is strongly dependent on atomic number and inversely on photon energy cubed.

  2. A capacitor stores 0.5 J of energy with a capacitance of 100 μF. What is the voltage across it?

    Answer: 100 V

    Using E = ½CV², V = √(2E/C) = √(2×0.5 / 100×10⁻⁶) = √10000 = 100 V.

  3. What does the term 'acoustic impedance' represent in ultrasound physics?

    Answer: The product of tissue density and sound speed

    Acoustic impedance Z = ρc, where ρ is the density of the medium and c is the speed of sound in that medium.

  4. In nuclear medicine, what does the effective half-life of a radiopharmaceutical account for?

    Answer: Both physical decay and biological elimination

    Effective half-life combines both physical half-life (radioactive decay) and biological half-life (clearance from the body): 1/T_eff = 1/T_phys + 1/T_biol.

  5. Which phenomenon explains why electrons do not spiral into the nucleus despite electrostatic attraction?

    Answer: Wave-particle duality and quantised energy levels

    Electrons occupy discrete quantised energy levels described by quantum mechanics; they cannot lose energy continuously and therefore cannot spiral inward.

  6. Which detector type is used in gamma cameras for nuclear medicine imaging?

    Answer: Sodium iodide scintillation crystal with photomultiplier tubes

    Gamma cameras use large sodium iodide (NaI:Tl) crystals that convert gamma photons to light, detected by an array of photomultiplier tubes.

  7. What is the de Broglie wavelength of an electron accelerated through a potential difference of 100 V? (m=9.11×10⁻³¹ kg, h=6.63×10⁻³⁴ Js, e=1.6×10⁻¹⁹ C)

    Answer: 0.123 nm

    λ = h/√(2meV) = 6.63×10⁻³⁴ / √(2×9.11×10⁻³¹×1.6×10⁻¹⁹×100) ≈ 0.123 nm.