SPI - Synthetic Personality Inventory Ability Test: Non-Verbal Reasoning Questions and Answers — Questions and Answers
Question 1: Observe the rules governing the following 3x3 matrix of figures. One cell is empty. Which of the answer choices logically completes the matrix? [Row 1: Large Square, Large Circle, Large Triangle] [Row 2: Medium Square, Medium Circle, Medium Triangle] [Row 3: Small Square, MISSING, Small Triangle]
- A Large Circle
- A Medium Square
- A Small Circle (Correct answer)
- A Small Triangle
Correct answer: A Small Circle
The logic of the matrix operates both horizontally and vertically. Horizontally, each row contains the same set of shapes (Square, Circle, Triangle). Vertically, each column contains the same shape but in decreasing size (Large, Medium, Small). The missing cell is in the 'Circle' column and the 'Small' row, therefore a Small Circle is the correct figure.
Question 2: Four of the following figures are similar in some logical way. Which of the following figures is the 'odd one out'?
- A shape with three straight sides and one curved side. (Correct answer)
- A six-pointed star.
- A regular octagon.
- A square.
Correct answer: A shape with three straight sides and one curved side.
The common characteristic among the six-pointed star, the regular octagon, and the square is that they are all polygons that can be drawn with straight lines only. The shape with three straight sides and one curved side does not fit this rule, as it incorporates a non-straight line.
Question 3: A figure undergoes a two-step transformation. The starting figure is an upward-pointing arrow. Step 1: Rotate the figure 90 degrees clockwise. Step 2: Flip the resulting figure horizontally. Which of the following answer choices shows the final figure?
- A downward-pointing arrow
- A leftward-pointing arrow (Correct answer)
- An upward-pointing arrow
- A rightward-pointing arrow
Correct answer: A leftward-pointing arrow
Starting with an upward-pointing arrow, Step 1 (rotate 90 degrees clockwise) results in a rightward-pointing arrow. Step 2 (flip horizontally) means reflecting it across a vertical axis. A rightward-pointing arrow, when flipped horizontally, becomes a leftward-pointing arrow.
Question 4: A set of five figures forms a logical sequence. The sequence shows a circle that is progressively filled with shaded segments in a clockwise direction, starting from the top segment. Figure 1 has the top 1/4 segment shaded. Figure 2 has the top and right 1/4 segments shaded. Figure 3 has the top, right, and bottom 1/4 segments shaded. What would Figure 5 in this sequence look like?
- A circle with only the top 1/4 segment shaded again. (Correct answer)
- A completely un-shaded circle.
- A circle with only the left 1/4 segment shaded.
- A completely shaded circle.
Correct answer: A circle with only the top 1/4 segment shaded again.
The pattern adds one shaded quadrant in a clockwise direction at each step. Figure 1 has one shaded quadrant. Figure 2 has two. Figure 3 has three. Figure 4 would have all four quadrants shaded. Following this pattern, Figure 5 would cycle back to the beginning, showing only the initial top 1/4 segment shaded again.
Question 5: Study the relationship between the first pair of figures to solve the analogy. A large square containing a small black circle is to a large square containing a small white circle AS a large triangle containing a small black square is to...?
- A small triangle containing a large black square.
- A large square containing a small white square.
- A large triangle containing a small white square. (Correct answer)
- A large triangle containing a small black circle.
Correct answer: A large triangle containing a small white square.
The relationship in the first pair shows that the large outer shape remains the same (a square), and the small inner shape also remains the same (a circle), but its shading inverts from black to white. Applying this logic to the second pair, the large outer triangle should remain a triangle, the small inner square should remain a square, and its shading should invert from black to white.
Question 6: Imagine a paper is folded in half vertically, and then folded in half again horizontally. A small circle is then punched through all layers in the corner where there are no folds. If the paper is completely unfolded, how many circular holes will there be?
- One
- Two
- Eight
- Four (Correct answer)
Correct answer: Four
The first vertical fold creates two layers. The second horizontal fold doubles the layers to four. Punching a hole through the corner with no folds (the open corner, not the folded corner) means the punch goes through all four layers of paper simultaneously. When unfolded, this will result in four distinct holes, one in each quadrant of the original paper.
Observe the rules governing the following 3x3 matrix of figures.
One cell is empty.
Which of the answer choices logically completes the matrix?
[Row 1: Large Square, Large Circle, Large Triangle]
[Row 2: Medium Square, Medium Circle, Medium Triangle]
[Row 3: Small Square, MISSING, Small Triangle]