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Police Math Area and Perimeter Calculations Flashcards

7 cards from real Police Math Test practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 Police Math Area and Perimeter Calculations flashcards as text

  1. An L-shaped scene is made of two rectangles: one 10 ft by 4 ft and one 6 ft by 3 ft. What is the total area?

    Answer: 58 square feet

    Area = (10 × 4) + (6 × 3) = 40 + 18 = 58 square feet.

  2. A rectangular cell is twice as long as it is wide, and its width is 7 feet. What is its perimeter?

    Answer: 42 feet

    Length = 2 × 7 = 14 ft; perimeter = 2(14 + 7) = 42 feet.

  3. A circular zone has a diameter of 10 feet. Using 3.14 for pi, what is its circumference?

    Answer: 31.4 feet

    Circumference = pi × diameter = 3.14 × 10 = 31.4 feet.

  4. A wall is 20 feet long and 8 feet high. If one can of paint covers 50 square feet, how many cans are needed?

    Answer: 4 cans

    Area = 20 × 8 = 160 sq ft; 160 ÷ 50 = 3.2, so 4 cans are needed.

  5. A rectangular lot has a perimeter of 100 feet and a length of 30 feet. What is its width?

    Answer: 20 feet

    Half the perimeter is 50; width = 50 − 30 = 20 feet.

  6. An officer tapes off a rectangle 16 ft by 9 ft but a 4 ft by 3 ft corner is excluded. What is the searchable area?

    Answer: 132 square feet

    Area = (16 × 9) − (4 × 3) = 144 − 12 = 132 square feet.

  7. A square garden has an area of 64 square feet. What is its perimeter?

    Answer: 32 feet

    Side = √64 = 8 ft; perimeter = 4 × 8 = 32 feet.