NBT Mathematics: Trigonometry Flashcards
7 cards from real NBT practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 7 NBT Mathematics: Trigonometry flashcards as text
Express cos(180° − θ) in terms of cos θ.
Answer: −cos θ
Using the co-function reduction formula, cos(180° − θ) = −cos θ.
The graph of y = cos x has a maximum value at x equal to:
Answer: 0°
y = cos x reaches its maximum value of 1 at x = 0° (and x = 360°, etc.).
Given sin 40° ≈ 0.643, what is cos 50°?
Answer: 0.643
Since 40° and 50° are complementary angles, cos 50° = sin 40° ≈ 0.643.
Solve cos θ = −1 for θ ∈ [0°, 360°].
Answer: 180°
cos θ = −1 only at θ = 180° within [0°, 360°].
What is the value of 2sin 60° − cos 30°?
Answer: √3/2
2sin 60° = 2 × (√3/2) = √3 and cos 30° = √3/2, so √3 − √3/2 = √3/2.
The graph of y = sin x is shifted 30° to the right. Its equation becomes:
Answer: y = sin(x − 30°)
A horizontal shift of 30° to the right replaces x with (x − 30°), giving y = sin(x − 30°).
Using the Sine Rule, in triangle ABC if a = 10, sin A = 0.5, and sin B = 0.8, find b.
Answer: 16
By the Sine Rule: b/sin B = a/sin A → b = 10 × 0.8/0.5 = 16.