NBT Mathematics: Exponents, Surds and Equations Flashcards
7 cards from real NBT practice questions. Tap to flip, then mark Knew It or Still Learning โ missed cards come back until you master them.
Read the first 7 NBT Mathematics: Exponents, Surds and Equations flashcards as text
Simplify: $2^{3} \times 2^{-5}$
Answer: $2^{-2}$
When multiplying powers with the same base, add the exponents: $3 + (-5) = -2$, giving $2^{-2}$.
Which of the following is equal to $\sqrt{75}$?
Answer: $5\sqrt{3}$
$\sqrt{75} = \sqrt{25 \times 3} = 5\sqrt{3}$.
Solve for $x$: $3^x = 81$
Answer: $x = 4$
$81 = 3^4$, so $x = 4$.
Rationalise the denominator: $\dfrac{6}{\sqrt{3}}$
Answer: $2\sqrt{3}$
$\dfrac{6}{\sqrt{3}} \times \dfrac{\sqrt{3}}{\sqrt{3}} = \dfrac{6\sqrt{3}}{3} = 2\sqrt{3}$.
Simplify: $\dfrac{x^6}{x^{-2}}$
Answer: $x^8$
Dividing powers with the same base: $6 - (-2) = 8$, giving $x^8$.
Solve for $x$: $x^2 - 5x + 6 = 0$
Answer: $x = 2$ or $x = 3$
Factorising: $(x-2)(x-3) = 0$, so $x = 2$ or $x = 3$.
Which expression is equal to $(27)^{2/3}$?
Answer: $9$
$(27)^{2/3} = (\sqrt[3]{27})^2 = 3^2 = 9$.