Practice Test GeeksMLPAO - Medical Laboratory Professionals Association of Ontario Practice Test
← All MLPAO Flashcard Decks

MLPAO Medical Laboratory Calculations Flashcards

7 cards from real MLPAO practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 MLPAO Medical Laboratory Calculations flashcards as text

  1. A patient's serum creatinine is 132 μmol/L. Convert this value to mg/dL. (Molecular weight of creatinine = 113.12 g/mol)

    Answer: 1.49 mg/dL

    Convert μmol/L to mg/dL: divide by 10 to get mmol/L (0.132), then multiply by MW (113.12): 0.132 × 113.12 / 10 = 1.49 mg/dL. Alternatively, μmol/L ÷ 88.4 ≈ mg/dL.

  2. A Levey-Jennings chart shows five consecutive QC values all falling above the mean on the same side. Which Westgard rule is violated?

    Answer: 10x rule

    The 10x rule (10ₓ) is violated when 10 consecutive control values fall on the same side of the mean, indicating a systematic shift or bias.

  3. You are preparing a working solution of NaCl at 0.9% (w/v). How many grams of NaCl are needed to prepare 500 mL of this solution?

    Answer: 4.5 g

    0.9% w/v means 0.9 g per 100 mL. For 500 mL: 0.9 g × (500/100) = 0.9 × 5 = 4.5 g.

  4. A urine microscopy report shows 15–20 RBCs per high-power field (HPF). This finding is best described as:

    Answer: Microscopic hematuria

    More than 3–5 RBCs/HPF is defined as microscopic hematuria. 15–20 RBCs/HPF is a clearly abnormal finding requiring clinical follow-up.

  5. A laboratory receives a hemolyzed specimen for potassium analysis. The measured potassium is 6.8 mmol/L. What is the most appropriate course of action?

    Answer: Reject the specimen, document hemolysis, and request a recollection

    Hemolysis releases intracellular potassium (up to 30× higher than plasma), causing falsely elevated results. The specimen must be rejected and recollected.

  6. Using the formula: Clearance (mL/min) = (U × V) / P, where U = urine creatinine (8,800 μmol/L), V = urine volume per minute (1.0 mL/min), and P = plasma creatinine (88 μmol/L), calculate the creatinine clearance.

    Answer: 100 mL/min

    Clearance = (U × V) / P = (8,800 × 1.0) / 88 = 8,800 / 88 = 100 mL/min.

  7. A technologist needs to dilute a patient sample that has a potassium result of 9.2 mmol/L (above linearity). After a 1:2 dilution with saline, the re-measured result is 4.8 mmol/L. What is the corrected patient potassium?

    Answer: 9.6 mmol/L

    Multiply the diluted result by the dilution factor: 4.8 × 2 = 9.6 mmol/L.