Mechanical Aptitude Forces and Motion Principles Flashcards
7 cards from real MECHANICAL APTITUDE practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 7 Mechanical Aptitude Forces and Motion Principles flashcards as text
A 500 kg car accelerates from 0 to 20 m/s in 10 seconds. What net force was applied?
Answer: 1000 N
a = 20/10 = 2 m/s²; F = ma = 500 × 2 = 1000 N.
Which of the following is an example of potential energy converting to kinetic energy?
Answer: A roller coaster descending a hill
As the roller coaster descends, gravitational potential energy converts into kinetic energy (speed).
A force is applied at an angle to the direction of motion. Which component does useful work?
Answer: The component parallel to motion
Work = F × d × cos(θ), so only the component of force parallel to the displacement does work.
If the speed of an object doubles, its kinetic energy:
Answer: Quadruples
KE = ½mv², so doubling v increases KE by a factor of 2² = 4 (quadruples).
A lever has a 3 m effort arm and a 1 m load arm. A 10 N effort is applied. What load can it lift?
Answer: 30 N
Using the lever principle: effort × effort arm = load × load arm → 10 × 3 = load × 1, so load = 30 N.
An object is in uniform circular motion. Which quantity remains constant?
Answer: Speed
In uniform circular motion, speed (magnitude) stays constant even though the direction of velocity constantly changes.
Which scenario demonstrates the conservation of momentum?
Answer: Two carts colliding and sticking together on a frictionless track
On a frictionless track with no external forces, the total momentum before and after collision is conserved.