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(Chemical and Physical Foundations) Flashcards

7 cards from real MCAT practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

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  1. A fluid flows through a pipe that narrows from a cross-sectional area of 0.04 m² to 0.01 m². If the velocity in the wide section is 2 m/s, what is the velocity in the narrow section?

    Answer: 8 m/s

    By the continuity equation, A₁v₁ = A₂v₂: 0.04×2 = 0.01×v₂; v₂ = 8 m/s.

  2. Which of the following statements about Le Chatelier's principle is correct when pressure is increased on the equilibrium N₂(g) + 3H₂(g) ⇌ 2NH₃(g)?

    Answer: Equilibrium shifts right to produce fewer moles of gas

    Increasing pressure favors the side with fewer moles of gas; 4 moles of reactant gas form 2 moles of NH₃, so equilibrium shifts right.

  3. Which of the following correctly describes a diamagnetic species?

    Answer: It contains only paired electrons and is weakly repelled by a magnetic field

    Diamagnetic species have all electrons paired; they experience weak repulsion in a magnetic field because paired electrons cancel each other's magnetic moments.

  4. A converging lens with focal length 10 cm forms an image of an object placed 30 cm away. Where is the image located?

    Answer: 15 cm on the opposite side

    Using 1/f = 1/do + 1/di: 1/10 = 1/30 + 1/di; di = 15 cm on the opposite side (real image).

  5. Which type of radioactive decay results in a product with the same mass number but a different atomic number?

    Answer: Beta decay

    Beta decay converts a neutron to a proton (or vice versa), changing Z by ±1 while mass number A remains constant.

  6. At constant temperature, if the pressure of an ideal gas is tripled, the volume becomes:

    Answer: One-third of the original

    Boyle's Law: P₁V₁ = P₂V₂; tripling pressure reduces volume to one-third at constant temperature.

  7. Which factor most directly determines the formal charge of an atom in a Lewis structure?

    Answer: The difference between valence electrons and (lone pair electrons + half of bonding electrons)

    Formal charge = valence electrons – lone pair electrons – ½(bonding electrons).