LSAT Logic Games: Grouping and Selection Games 3 — Questions and Answers
Question 1: A hiring committee must select exactly 3 employees from applicants J, K, L, M, N. The rule states K and L cannot both be hired. Which scenario is impossible?
- J, K, M are hired
- J, L, N are hired
- K, L, M are hired (Correct answer)
- J, M, N are hired
Correct answer: K, L, M are hired
K and L cannot both be hired, so any group containing both violates the constraint.
Question 2: In a defined grouping game, the rule 'No more than 2 members of Group A can be selected' functions primarily as:
- A minimum constraint on Group A
- A maximum constraint on Group A (Correct answer)
- A biconditional linking Groups A and B
- An ordering constraint for Group A
Correct answer: A maximum constraint on Group A
The phrase 'no more than 2' sets an upper limit (maximum) on the size of Group A.
Question 3: Six items—A, B, C, D, E, F—are split into Group 1 (3 items) and Group 2 (3 items). Rule: If A is in Group 1, then C is in Group 2. Rule: If D is in Group 2, then B is in Group 1. If A and D are both in Group 1, which must be true?
- C and B are both in Group 1
- C is in Group 2 and B is in Group 1 (Correct answer)
- C and B are both in Group 2
- D's placement is undetermined
Correct answer: C is in Group 2 and B is in Group 1
A in Group 1 forces C to Group 2; D in Group 1 means D is NOT in Group 2, so the second rule does not fire—but B's placement from the second rule requires D in Group 2 to trigger, which doesn't occur; however C must be in Group 2 from rule 1.
Question 4: A selection game has 7 candidates and requires exactly 4 to be chosen. The rule states: 'If X is chosen, Y is not chosen, and if Y is chosen, Z is chosen.' How many acceptable groups include Y?
- Groups with Y must also include Z and exclude X (Correct answer)
- Groups with Y must also include X
- Groups with Y must exclude Z
- Y cannot appear in any valid group
Correct answer: Groups with Y must also include Z and exclude X
Y chosen triggers Z chosen (Y→Z) and precludes X (contrapositive of X→not Y means Y→not X).
Question 5: In LSAT grouping games, a 'floater' element is best described as:
- An element tied to the most constraints
- An element with no rules governing its placement (Correct answer)
- An element that must always be selected
- An element that can only go in one group
Correct answer: An element with no rules governing its placement
A floater has no specific rules attached to it, so it can be placed freely wherever slots allow.
Question 6: Seven students—P, Q, R, S, T, U, V—are assigned to clubs 1 and 2. Club 1 has exactly 4 members; Club 2 has exactly 3. If P and Q must be in the same club and R and S must be in different clubs, what is the maximum number of students whose placement is fully determined by placing P in Club 1?
- 1
- 2 (Correct answer)
- 3
- 4
Correct answer: 2
Placing P in Club 1 forces Q to Club 1 as well, determining exactly 2 placements directly.
Question 7: A game requires selecting 3 from {A, B, C, D, E}. The constraint is: 'Exactly one of B or C must be selected.' If B is not selected, which is true?
- C is not selected
- C must be selected (Correct answer)
- A must be selected
- The selection is invalid
Correct answer: C must be selected
The 'exactly one' constraint means if B is out, C must be in to satisfy the requirement.
LSAT Logic Games: Grouping and Selection Games 3
A hiring committee must select exactly 3 employees from applicants J, K, L, M, N.
The rule states K and L cannot both be hired.
Which scenario is impossible?