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Journeyman Electrician's Boxes and Enclosures Flashcards

7 cards from real Journeyman Electrician’s Exam practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 Journeyman Electrician's Boxes and Enclosures flashcards as text
  1. According to NEC Table 314.16(B), what is the volume allowance assigned to each 14 AWG conductor for box fill calculations?

    Answer: 2.00 cubic inches

    NEC Table 314.16(B) assigns a volume allowance of 2.00 cubic inches for each 14 AWG conductor in box fill calculations.

  2. Per NEC 314.16(B)(4), how does a duplex receptacle (wiring device) count in a box fill calculation?

    Answer: Two conductors based on the largest AWG in the box

    NEC 314.16(B)(4) states each wiring device (switch or receptacle) counts as two conductors based on the largest AWG conductor present in the box.

  3. Per NEC 314.16(B)(5), all equipment grounding conductors (EGCs) inside a box collectively count as how many conductors in box fill?

    Answer: One conductor based on the largest EGC present

    NEC 314.16(B)(5) requires all EGCs together to be counted as a single conductor based on the largest EGC in the box.

  4. A 4-inch square metal box 1-1/2 inches deep has a listed volume of 21 cubic inches. Using only 12 AWG conductors (no devices or clamps), how many conductors are permitted?

    Answer: 9 conductors

    Each 12 AWG conductor occupies 2.25 cubic inches; 21 ÷ 2.25 = 9.33, which rounds down to 9 conductors maximum.

  5. Per NEC 314.16(B)(2), how do all internal cable clamps inside a box count toward box fill?

    Answer: One conductor (all clamps together) based on the largest AWG in the box

    NEC 314.16(B)(2) requires all internal cable clamps as a group to count as a single conductor based on the largest wire size in the box.

  6. A box contains three 14 AWG conductors, one duplex receptacle, and one equipment grounding conductor. What is the minimum required box volume?

    Answer: 12.00 cubic inches

    Calculation: 3 conductors × 2.00 + device × (2 × 2.00) + EGC group × 2.00 = 6.00 + 4.00 + 2.00 = 12.00 cubic inches minimum.

  7. Per NEC 314.16(B)(1), a conductor that passes through a box without any splice or termination counts in box fill as:

    Answer: One conductor

    NEC 314.16(B)(1) requires each pass-through conductor to be counted once because it still occupies space inside the box.