Semiconductor Device Principles Flashcards
7 cards from real ISCET practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 7 Semiconductor Device Principles flashcards as text
What is the diffusion capacitance of a forward-biased p-n junction proportional to?
Answer: Forward bias current
Diffusion capacitance is proportional to the DC forward bias current because more current means more stored minority charge.
In an enhancement-mode N-channel MOSFET, the device is normally:
Answer: OFF with zero gate bias and turned ON by positive VGS above threshold
Enhancement-mode MOSFETs have no channel at VGS = 0 and require VGS > VTH to invert the channel and allow drain current.
What is the transconductance (gm) of a MOSFET in the saturation region given ID = 4 mA and VGS – VTH = 2 V?
Answer: 4 mA/V
In saturation, gm = 2·ID / (VGS – VTH) = (2 × 4 mA) / 2 V = 4 mA/V.
Which type of breakdown in a reverse-biased diode is dominant at voltages below approximately 5 V in heavily doped junctions?
Answer: Zener (tunneling) breakdown
Zener (band-to-band tunneling) breakdown dominates in heavily doped junctions at low reverse voltages (below ~5 V) where the depletion region is very narrow.
The pinch-off voltage (VP) of a JFET is the value of VGS at which:
Answer: The channel is completely depleted and drain current drops to zero
Pinch-off voltage is the gate-to-source voltage that fully depletes the channel, cutting off drain current (IDSS approaches zero).
A silicon BJT has β = 100 and IC = 5 mA. What is the approximate base current IB?
Answer: 0.05 mA
IB = IC / β = 5 mA / 100 = 0.05 mA (50 µA).
What physical phenomenon causes the channel-length modulation effect in short-channel MOSFETs?
Answer: Extension of the drain depletion region into the channel, reducing effective channel length
As VDS increases beyond pinch-off, the drain depletion region expands toward the source, shortening the effective channel and increasing drain current.