Probability and Combinatorics Flashcards
6 cards from real IMSA practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 6 Probability and Combinatorics flashcards as text
What is the probability of NOT rolling a 3 on a standard die?
Answer: 5/6
P(not 3) = 1 − P(3) = 1 − 1/6 = 5/6.
In how many ways can a president and vice president be chosen from 8 candidates?
Answer: 56
Order matters, so P(8,2) = 8 × 7 = 56.
A family has 3 children. What is the probability that all 3 are girls (assuming equal probability)?
Answer: 1/8
P(GGG) = (1/2)³ = 1/8, since each birth is independent.
A lottery requires picking 2 numbers from 1−10 without replacement. How many combinations are possible?
Answer: 45
C(10,2) = 10!/(2! × 8!) = (10 × 9)/2 = 45.
If P(A) = 0.6, what is P(not A)?
Answer: 0.4
P(not A) = 1 − P(A) = 1 − 0.6 = 0.4.
Which of the following equals C(5,2)?
Answer: 10
C(5,2) = 5!/(2! × 3!) = (5 × 4)/(2 × 1) = 10.