Practice Test GeeksIBEW - Aptitude Test Practice Test
← All IBEW Flashcard Decks

Algebra and Functions Flashcards

6 cards from real IBEW practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 6 Algebra and Functions flashcards as text

  1. An electrical contractor purchases a spool of wire that is 1,250 feet long. If they use 3/5 of the spool for one job and then 1/4 of the remaining wire for a second job, how many feet of wire are left on the spool?

    Answer: 375 feet

    First, calculate the amount of wire used in the first job: 1,250 feet * (3/5) = 750 feet. The remaining wire is 1,250 - 750 = 500 feet. For the second job, they use 1/4 of the remaining wire: 500 feet * (1/4) = 125 feet. The final amount of wire left is 500 - 125 = 375 feet.

  2. Solve the following equation for x: 4(x + 2) - 2x = 14

    Answer: x = 3

    First, distribute the 4 into the parentheses: 4x + 8 - 2x = 14. Then, combine the x terms: 2x + 8 = 14. Subtract 8 from both sides of the equation: 2x = 6. Finally, divide by 2 to solve for x: x = 3.

  3. Which of the following expressions is the result of factoring the polynomial x² - 5x - 14?

    Answer: (x + 2)(x - 7)

    To factor the quadratic polynomial x² - 5x - 14, we need to find two numbers that multiply to -14 and add up to -5. These two numbers are +2 and -7. Therefore, the factored form is (x + 2)(x - 7).

  4. If f(x) = 3x² + 2x - 5, what is the value of f(-3)?

    Answer: 16

    To find f(-3), substitute -3 for every x in the function: f(-3) = 3(-3)² + 2(-3) - 5. Following the order of operations, first calculate the exponent: 3(9) + 2(-3) - 5. Then, perform the multiplication: 27 - 6 - 5. Finally, perform the subtraction from left to right: 21 - 5 = 16.

  5. A circuit requires two resistors, R1 and R2. The resistance of R1 is 5 ohms more than twice the resistance of R2. The total resistance of the circuit is 32 ohms. What is the resistance of R2?

    Answer: 9 ohms

    Let R2 be 'x'. Then R1 can be expressed as '2x + 5'. Since the total resistance is the sum of the individual resistances, the equation is (2x + 5) + x = 32. Combine the like terms: 3x + 5 = 32. Subtract 5 from both sides: 3x = 27. Divide by 3 to find x: x = 9. So, the resistance of R2 is 9 ohms.

  6. Simplify the following algebraic expression: (4x²y³)(3xy⁴)

    Answer: 12x³y⁷

    To simplify this expression, multiply the coefficients (4 * 3 = 12). Then, for the variables, add the exponents of the like bases. For x, the exponents are 2 and 1, so x^(2+1) = x³. For y, the exponents are 3 and 4, so y^(3+4) = y⁷. The simplified expression is 12x³y⁷.