Practice Test Geeks(GD&T) Geometric Dimensioning and Tolerancing Certification Practice Test
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Position Tolerancing Calculations Flashcards

7 cards from real GD&T practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 Position Tolerancing Calculations flashcards as text

  1. A CMM report shows a hole axis deviated 0.18 mm in X and 0.24 mm in Y from true position. The diametral position error is:

    Answer: ⌀0.60

    Radial = √(0.18² + 0.24²) = √(0.0324 + 0.0576) = √0.09 = 0.30; diametral = 2 × 0.30 = ⌀0.60.

  2. Which of the following best defines 'resultant condition' for an external feature (pin) at MMC with position tolerance?

    Answer: LMC + position tolerance

    Resultant condition for an external feature = LMC + position tolerance, representing the worst-case outer boundary at the smallest actual size.

  3. When calculating position for a slotted hole (elongated feature), GD&T allows specifying two position tolerance values. What do the two values control separately?

    Answer: Tolerance in the length direction and tolerance in the width direction

    Two values allow a larger position tolerance along the slot's length direction and a tighter tolerance across its width, reflecting functional assembly requirements.

  4. A part has four tapped holes (fixed fastener situation) to mate with a cover plate. The clearance holes in the cover are ⌀6.5 mm (MMC) and the screws are ⌀6.0 mm (MMC). What position tolerance should each part receive?

    Answer: ⌀0.25 each

    Floating fastener: T_each = (6.5 − 6.0) / 2 = 0.25 mm; each part gets ⌀0.25 position tolerance.

  5. A tolerance analysis requires that the total positional contribution of a feature be within ⌀0.8. If the feature is at actual size 20.3 mm with MMC = 20.0 mm and stated position of ⌀0.3 (M), does the feature pass?

    Answer: Yes — total allowable is ⌀0.6, within ⌀0.8 requirement

    Total allowable = ⌀0.3 + (20.3 − 20.0) = ⌀0.6; since ⌀0.6 ≤ ⌀0.8, the feature passes the stack requirement.

  6. The 'simultaneous requirement' rule in GD&T means that position callouts sharing the same datums in the same order:

    Answer: Must be verified simultaneously as a single pattern

    Under the simultaneous requirement, feature control frames with identical datum references in the same order are treated as one pattern and must be verified in a single gauge setup.

  7. A true position tolerance of ⌀0.2 is specified for a hole. The CMM calculates a diametral position error of ⌀0.19. The hole is at LMC. Which conclusion is correct?

    Answer: The hole passes because ⌀0.19 ≤ ⌀0.2 regardless of size (RFS)

    With no modifier shown (RFS default), the tolerance is ⌀0.2 at all sizes; since ⌀0.19 ≤ ⌀0.2, the hole passes.