Excel VBA Excel VBA Error Handling & Debugging 2

Question 1

Which VBA debugging action executes code one line at a time, including stepping into called procedures?

Accepted Answer

Step Into

Answer

Breakpoints

Answer

Watch Window

Answer

Immediate Window

Question 2

What is a breakpoint in the context of VBA debugging?

Accepted Answer

A marker that pauses execution when that line is reached

Answer

A line of code that automatically throws an error

Answer

A special comment that stops code from running

Answer

An error that permanently breaks the code flow

Question 3

Which window in the VBA IDE allows you to type and execute VBA statements interactively without running a full procedure?

Accepted Answer

Immediate Window

Answer

Watch Window

Answer

Locals Window

Answer

Output Window

Question 4

What information does the Locals Window display during VBA debugging?

Accepted Answer

All variables in the current procedure scope with their current values and types

Answer

All variables declared across the entire project

Answer

A list of all VBA error numbers and descriptions

Answer

The complete call stack of procedure invocations

Question 5

Which VBA debugging feature lets you monitor a specific variable or expression and optionally pause execution when its value changes?

Accepted Answer

Watch Expressions

Answer

Breakpoints

Answer

Step Over

Answer

Trace Variables

Question 6

What is the key difference between 'Step Into' (F8) and 'Step Over' (Shift+F8) during VBA debugging?

Accepted Answer

Step Into enters called procedures line by line; Step Over executes them as a single step

Answer

Step Into runs all code at once; Step Over runs one line at a time

Answer

Step Over is faster than Step Into in all scenarios

Answer

Step Into handles errors automatically; Step Over skips them

Question 7

Which VBA statement outputs values and messages to the Immediate Window during code execution for logging purposes?

Accepted Answer

Debug.Print

Answer

Print.Debug

Answer

Debug.Write

Answer

Console.WriteLine