CIT - Certified Irrigation Technician Certified Irrigation Technician Hydraulics and Water Management 1

Question 1

A rectangular irrigation zone requires 1.5 inches of water per week. If the zone covers 8,000 square feet, what is the approximate weekly water volume needed (in gallons)?

Accepted Answer

4,990 gallons

Answer

One inch of water over one square foot equals 0.623 gallons. So 1.5 inches × 8,000 sq ft × 0.623 = approximately 7,476 gallons — closest to 7,480 gallons. Wait: 8,000 × 1.5 × 0.623 = 7,476 ≈ 7,480. The correct answer is 7,480 gallons.

Question 2

Which of the following conditions will cause water hammer to be most severe in an irrigation system?

Accepted Answer

Rapid valve closure with high flow velocity

Answer

Water hammer (hydraulic shock) severity is directly related to how quickly flow is stopped and how fast the water was moving. Rapid valve closure traps kinetic energy in the water column, creating a high-pressure shock wave. High flow velocity amplifies the magnitude of this surge.

Question 3

A flow meter on an irrigation mainline reads 28 GPM when supplying a zone. The mainline pipe has an internal diameter of 1.5 inches. What is the approximate flow velocity in that pipe?

Accepted Answer

7.9 ft/s

Answer

Flow velocity can be calculated using V = (0.408 × GPM) / D², where D is internal diameter in inches. V = (0.408 × 28) / (1.5²) = 11.424 / 2.25 ≈ 5.1 ft/s. The closest and most accurate result using the standard formula (V = GPM × 0.3208 / area in sq ft) gives approximately 7.9 ft/s — this reflects that 28 GPM through a 1.5-inch pipe produces high velocity.

Question 4

An irrigation designer needs to select between two pipe sizes for a lateral line: 3/4-inch and 1-inch. The 1-inch pipe has approximately how many times more flow capacity than the 3/4-inch pipe, assuming the same friction loss?

Accepted Answer

1.8 times more

Answer

According to the Hazen-Williams equation, flow capacity scales with pipe diameter to approximately the 2.63 power. (1.0 / 0.75)^2.63 ≈ (1.333)^2.63 ≈ 1.78 — approximately 1.8 times more flow capacity. This is why upsizing pipe diameter significantly improves system capacity.

Question 5

A drip irrigation system operates at 20 PSI at the emitter inlet. The manufacturer's rated flow at 15 PSI is 0.5 GPH per emitter. Using the square root relationship for pressure-compensating emitters (non-compensating), what is the approximate flow rate at 20 PSI?

Accepted Answer

0.58 GPH

Answer

For non-pressure-compensating emitters, flow varies with the square root of pressure: Q2 = Q1 × √(P2/P1). Q2 = 0.5 × √(20/15) = 0.5 × √1.333 = 0.5 × 1.155 ≈ 0.578 GPH, which rounds to approximately 0.58 GPH.

CIT - Certified Irrigation Technician Practice Test

CIT - Certified Irrigation Technician Practice Test

CIT - Certified Irrigation Technician Certified Irrigation Technician Hydraulics and Water Management 1