CFAT Problem Solving 2 — Questions and Answers
Question 1: A military convoy travels 240 km in 3 hours. What is its average speed?
- 60 km/h
- 70 km/h
- 80 km/h (Correct answer)
- 90 km/h
Correct answer: 80 km/h
Average speed = distance ÷ time = 240 ÷ 3 = 80 km/h.
Question 2: A soldier uses 40% of his rations on day 1, then 25% of the remainder on day 2. What percentage of the original rations remains?
- 35%
- 40%
- 45% (Correct answer)
- 50%
Correct answer: 45%
After day 1, 60% remains; 60% × 75% = 45% of original.
Question 3: If 3 soldiers can set up camp in 6 hours, how long would 9 soldiers take at the same rate?
- 1 hour
- 2 hours (Correct answer)
- 3 hours
- 4 hours
Correct answer: 2 hours
Total work = 3 × 6 = 18 soldier-hours; 18 ÷ 9 soldiers = 2 hours.
Question 4: A map has a scale of 1:50,000. Two points are 4 cm apart on the map. What is the actual distance?
- 1 km
- 2 km (Correct answer)
- 5 km
- 20 km
Correct answer: 2 km
4 cm × 50,000 = 200,000 cm = 2,000 m = 2 km.
Question 5: A magazine holds 48 rounds. A soldier fires 1/3 in the morning and 1/4 of the remainder in the afternoon. How many rounds remain?
- 16
- 20
- 24 (Correct answer)
- 28
Correct answer: 24
After morning: 48 − 16 = 32; after afternoon: 32 − 8 = 24 rounds remain.
Question 6: What is the next number in the sequence: 3, 7, 15, 31, 63, ?
- 95
- 112
- 127 (Correct answer)
- 131
Correct answer: 127
Each term is doubled and 1 is added: 63 × 2 + 1 = 127.
Question 7: A squad of 12 soldiers shares 96 kg of equipment equally. If 4 soldiers are reassigned, how much more must each remaining soldier carry?
- 2 kg
- 3 kg
- 4 kg (Correct answer)
- 6 kg
Correct answer: 4 kg
Original share: 96 ÷ 12 = 8 kg; new share: 96 ÷ 8 = 12 kg; difference = 4 kg.
CFAT Problem Solving 2
A military convoy travels 240 km in 3 hours.
What is its average speed?