CFAT - Canadian Forces Aptitude Problem Solving: Basic Math Questions and Answers

Question 1

A supply truck travels 240 km from Base A to Base B at a constant speed of 80 km/h. The driver stops for a 30-minute break during the trip. What is the total time elapsed from departure to arrival?

Accepted Answer

3.5 hours

Answer

First, calculate the driving time by dividing the distance by the speed: Time = Distance / Speed = 240 km / 80 km/h = 3 hours. Next, add the break time to the driving time. The break is 30 minutes, which is 0.5 hours. Total time = 3 hours + 0.5 hours = 3.5 hours.

Question 2

A platoon has 300 recruits. In the first month of training, 15% of the recruits drop out. How many recruits remain in the platoon?

Accepted Answer

255

Answer

To find the number of recruits who dropped out, calculate 15% of 300: 0.15 * 300 = 45. To find the number of remaining recruits, subtract the dropouts from the initial total: 300 - 45 = 255.

Question 3

Private Smith can paint a wall in 3 hours, while Private Jones can paint the same wall in 6 hours. If they work together, how long will it take them to paint the wall?

Accepted Answer

2 hours

Answer

First, determine their individual work rates. Smith's rate is 1/3 of the wall per hour. Jones's rate is 1/6 of the wall per hour. Their combined rate is the sum of their individual rates: 1/3 + 1/6 = 2/6 + 1/6 = 3/6 = 1/2 wall per hour. To find the total time, take the reciprocal of their combined rate: 1 / (1/2) = 2 hours.

Question 4

A fuel mixture for a generator requires oil and gasoline in a ratio of 1:50. To prepare 102 litres of this mixture, how many litres of oil are required?

Accepted Answer

2 litres

Answer

The ratio 1:50 means there are 1 + 50 = 51 total parts in the mixture. To find the volume of one part, divide the total volume by the total number of parts: 102 litres / 51 parts = 2 litres per part. Since oil makes up 1 part of the ratio, 1 part * 2 litres/part = 2 litres of oil are required.

Question 5

A rectangular training field has an area of 5,000 square metres. If the length of the field is twice its width, what is the perimeter of the field?

Accepted Answer

300 m

Answer

Let the width be 'w'. Then the length is '2w'. The area is length × width, so 2w × w = 5000, which simplifies to 2w² = 5000. Divide by 2 to get w² = 2500. The square root of 2500 is 50, so the width is 50 m. The length is 2 × 50 = 100 m. The perimeter is 2 × (length + width) = 2 × (100 + 50) = 2 × 150 = 300 m.

(CFAT) Canadian Forces Aptitude Test Practice Test

(CFAT) Canadian Forces Aptitude Test Practice Test

CFAT - Canadian Forces Aptitude Problem Solving: Basic Math Questions and Answers