Control Systems Theory Flashcards
7 cards from real BEE practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 7 Control Systems Theory flashcards as text
The phase margin of a stable feedback system is measured at the frequency where the open-loop magnitude is:
Answer: 0 dB (unity gain)
Phase margin is the additional phase lag at the gain crossover frequency (where |G(jω)H(jω)| = 1, or 0 dB) before the system becomes unstable.
Which of the following statements about the root locus is correct?
Answer: Branches start at open-loop poles and end at open-loop zeros (or infinity)
Root locus branches begin at open-loop poles (K=0) and terminate at open-loop zeros or travel to infinity along asymptotes as K→∞.
A second-order system with ζ = 0.5 and ωn = 10 rad/s has a damped natural frequency (ωd) of:
Answer: 8.66 rad/s
The damped natural frequency is ωd = ωn√(1−ζ²) = 10√(1−0.25) = 10√0.75 ≈ 8.66 rad/s.
In the Nyquist stability criterion, encirclements of the −1+j0 point in the clockwise direction are counted to determine:
Answer: The number of unstable closed-loop poles
By the Nyquist criterion, N = Z − P, where N is clockwise encirclements of −1, P is open-loop RHP poles, and Z is closed-loop RHP poles (instability count).
A system is said to be observable if:
Answer: The initial state can be determined from the output over a finite time interval
Observability means that every initial state x(0) can be uniquely determined by observing the output y(t) over a finite time interval.
Which compensator is most effective at improving the steady-state accuracy of a control system without significantly affecting transient response?
Answer: Lag compensator
A lag compensator increases low-frequency gain to reduce steady-state error while placing its pole-zero pair far below the crossover frequency, minimally affecting transient response.
For a unity-feedback system with open-loop transfer function G(s) = K/[s(s+4)], what value of K places both closed-loop poles at s = −2?
Answer: K = 4
Closed-loop characteristic equation: s² + 4s + K = 0; for double root at s = −2, we need (s+2)² = s² + 4s + 4, so K = 4.