Power Redundancy & UPS Systems Flashcards
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Read the first 7 Power Redundancy & UPS Systems flashcards as text
Which UPS topology provides zero transfer time during a utility power failure?
Answer: Double-conversion (online) UPS
Double-conversion online UPS continuously powers the load from the inverter, so there is no transfer time when utility power fails.
In a 2N power redundancy configuration, what happens to the total capacity when one PDU path fails?
Answer: The remaining path carries 100% of the load at full rated capacity
In a 2N configuration, each path is sized to carry 100% of the load, so a single path failure results in the surviving path assuming the full load.
A static transfer switch (STS) typically has a transfer time measured in:
Answer: Milliseconds (4–8 ms)
Static transfer switches typically switch between power sources within 4–8 milliseconds, fast enough for most IT equipment.
Which of the following best describes an N+1 UPS redundancy model?
Answer: One extra UPS module is deployed beyond the minimum needed to support the load
N+1 redundancy means one additional UPS module is added beyond the N modules required to carry the load, allowing any single module to fail without service interruption.
What is the primary advantage of a modular UPS over a traditional monolithic UPS in a data center?
Answer: Scalability and hot-swap capability for individual power modules
Modular UPS systems allow individual power modules to be added or replaced without shutting down the system, enabling scalable and maintainable redundancy.
When performing a UPS maintenance bypass, what is the critical safety concern the technician must verify before switching to bypass?
Answer: That the bypass source is synchronized with the UPS output
Before engaging maintenance bypass, the bypass source must be synchronized in phase and voltage with the UPS output to prevent a voltage step or surge to the load.
A data center UPS is rated at 500 kVA with a 0.9 power factor. What is the maximum kW load it can support?
Answer: 450 kW
Real power (kW) = apparent power (kVA) × power factor, so 500 kVA × 0.9 = 450 kW.