AMC12 Complex Numbers 1 β Questions and Answers
Question 1: If z = 3 + 4i, what is |z|, the modulus of z?
- 5 (Correct answer)
- 7
- 25
- 4
Correct answer: 5
The modulus is β(3Β² + 4Β²) = β(9 + 16) = β25 = 5.
Question 2: What is the product (2 + 3i)(1 β 2i)?
- 2 β i
- 8 β i (Correct answer)
- β4 + 7i
- 8 + i
Correct answer: 8 β i
Expanding: 2 β 4i + 3i β 6iΒ² = 2 β i + 6 = 8 β i, since iΒ² = β1.
Question 3: What is i^23?
- 1
- i
- β1
- βi (Correct answer)
Correct answer: βi
Since i repeats with period 4 and 23 β‘ 3 (mod 4), i^23 = i^3 = βi.
Question 4: If z = 1 + i, what is z^4?
- 4
- β4 (Correct answer)
- 4i
- β4i
Correct answer: β4
zΒ² = (1+i)Β² = 2i, so zβ΄ = (2i)Β² = 4iΒ² = β4.
Question 5: What is the real part of (3 + 4i) / (1 + 2i)?
- 3/5
- 11/5 (Correct answer)
- β1/5
- 2
Correct answer: 11/5
Multiply numerator and denominator by the conjugate (1β2i): (3+4i)(1β2i)/5 = (11β2i)/5, giving real part 11/5.
Question 6: If zβ = 1 + 2i and zβ = 2 β i, what is zβ + zβ?
- 3 + i (Correct answer)
- 3 β i
- β1 + 3i
- 1 + 3i
Correct answer: 3 + i
Add real and imaginary parts separately: (1+2) + (2β1)i = 3 + i.
Question 7: If z = cos(Ο/6) + iΒ·sin(Ο/6), what is z + zΜ (z plus its complex conjugate)?
- 0
- 1
- β3 (Correct answer)
- 2
Correct answer: β3
z = β3/2 + i/2 and zΜ = β3/2 β i/2, so z + zΜ = β3 (the imaginary parts cancel).
If z = 3 + 4i, what is |z|, the modulus of z?